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grandymaker [24]
3 years ago
13

What is the value of the underlined number of the underlined number 1,284 5,493

Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0
What are the undefined numbers?
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The reflected figure will appear in quadrant 3, C.

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2 years ago
Bus stop Restaurant sell 3/4 as many cheeseburgers as they do with hamburgers on any given day. If there are a total of 42 burge
schepotkina [342]

Answer:

24cb 18 hb

Step-by-step explanation:

Let's call C the number of cheese burger sold and H the number of hamburgers.

As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:

C= (3/4)H (equation 1)

The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:

C + H = 42

Replacing C by its value of eq. 1:

(3/4)H + H = 42

(3/4)H + (4/4)H = 42

(7/4) H = 42

Dividing both sides by (7/4)

H = 42/(7/4)

H= 42*(4/7)

H= (42/7)*4

H= 6*4

H=24

Then, C is:

C=(3/4)H

C=(3/4)*24

C= 3*24/4

C=72/4

C=18

We can verify it summing C+H

C+H=24+18=42 verified!

6 0
3 years ago
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year. If you had purchased a h
Kipish [7]

Answer:

The home would be worth $249000 during the year of 2012.

Step-by-step explanation:

The price of the home in t years after 2004 can be modeled by the following equation:

P(t) = P(0)(1+r)^{t}

In which P(0) is the price of the house in 2004 and r is the growth rate.

Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.

This means that r = 0.047

$172000 in 2004

This means that P(0) = 172000

What year would the home be worth $ 249000 ?

t years after 2004.

t is found when P(t) = 249000. So

P(t) = P(0)(1+r)^{t}

249000 = 172000(1.047)^{t}

(1.047)^{t} = \frac{249000}{172000}

\log{(1.047)^{t}} = \log{\frac{249000}{172000}}

t\log(1.047) = \log{\frac{249000}{172000}}

t = \frac{\log{\frac{249000}{172000}}}{\log(1.047)}

t = 8.05

2004 + 8.05 = 2012

The home would be worth $249000 during the year of 2012.

8 0
3 years ago
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