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kifflom [539]
3 years ago
8

ALEX HAS 5 LIZARDS. HE DIVIDES THEM EQUALLY AMONG 5 CAGES. HOW MANY LIZARDS DOES ALEX PUT IN EACH CAGE?

Mathematics
2 answers:
dlinn [17]3 years ago
8 0
1 in each cage if he has 5 cages and 5 lizards  he could put them in each cage

poizon [28]3 years ago
7 0
Simple, 1 lizard per cage.  5 divided by 5 is 1.
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Please help!! <br> it says what I wrote is too short so
kvv77 [185]

Answer:

50 cents The red on the right end.

Step-by-step explanation:

Let the chocolate chip cookies = x

Let the jumbo popcorn = y

Julie

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-2x = - 1                     The y's disappear. You are left with 1 dollar (negative). Divide by - 2

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Each cookie costs 50c

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A rectangular prism has a length of 4 cm a width of 6 cm and a height of 3 cm what is it’s volume
liraira [26]

Answer: 72

Step-by-step explanation:

8 0
3 years ago
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An overdraft is a check that cannot be covered by funds in the account.
Degger [83]

Answer:

True

Step-by-step explanation:

7 0
3 years ago
Need a little help with one please
Pani-rosa [81]

Answer:

That would be the side-side-side (SSS) postulate, which states that if all the sides of a triangle are in a fixed ratio to all the corresponding sides of another triangle, then the two triangles are said to be congruent.

Step-by-step explanation:

Looking at triangles ABC and DEF, we notice that:

\frac{AB}{DE} = \frac{AC}{DF}=\frac{BC}{EF}

since

\frac{3}{18} = \frac{6}{36}=\frac{7}{42}=\frac{1}{6}

Let me know if you have further questions.

4 0
3 years ago
Tickets for the basketball game were sold at $4.00 for adults and $2.50 for students. If 320 tickets were sold for a total of $1
makkiz [27]

The problem based on condition are solved using the unknown variables. The number of tickets sold to the student are 120 and the number of tickets sold to the adults are 200.

Given information-

The price of the tickets for the basketball game for adults is $4.00.

The price of the tickets for the basketball game for students is $2.50.

<h3>Variables</h3>

Variables are the unknown and the value of the variables depend on the other variables in the equation. The above problem can be solved defining the variables from the given condition.

Let the total tickets purchased by the students is<em> x</em> and the total tickets porches by the adults is <em>y.</em>

As the total tickets sold for the game is $320. Thus,

\begin{aligned}\\&#10;x+y&=320\\&#10;y&=320-x\\&#10;\end                    .......1

Now as the total money with ticket selling is $1100. Thus,

2.5x+4y=110

Keep the value of u from the equation 1 in the above equation. We get,

\begin{aligned}&#10;2.5x+4(320-x)&=1100\\&#10;2.5x+1280-4x&=1100\\&#10;-1.5x&=1100-1280\\&#10;-1.5x&=-180\\&#10;x&=\dfrac{180}{1.5} \\&#10;x&=120\\&#10;\end

Thus the number of tickets sold to the student are 120.

Keep this value in equation 1,

y=320-x\\&#10;y=320-120\\&#10;y=200

Thus the number of tickets sold to the adults are 200.

Hence the number of tickets sold to the student are 120 and the number of tickets sold to the adults are 200.

brainly.com/question/787279

8 0
2 years ago
Read 2 more answers
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