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Diano4ka-milaya [45]
2 years ago
7

I need someone to help me with my homework

Mathematics
2 answers:
Gala2k [10]2 years ago
4 0

Answer:

okay................

vfiekz [6]2 years ago
3 0
What is it ?.............
You might be interested in
Monica has $20. She needs to buy a gallon of milk that costs $2.50. She also wants to buy yogurt, which costs $1.20 a cup. What
Kitty [74]

We are given : Cost of a gallon of milk = $2.50.

Cost of a cup of yogurt = $1.20.

Total money Monica has = $20.

Number of cups of yogurt Monica can buy = x.

And inequality made is also correct

1.20x + 2.5 ≤ 20.

Now, we need to solve it for x.

Subtracting 2.5 from both sides, we get

1.20x + 2.5 -2.5 ≤ 20 - 2.5.

1.20x ≤ 17.5

Dividing both sides by 1.20, we get

1.20x/1.20 ≤ 17.5/1.20.

x ≤ 14.5833...

Because it's less than 15, so final answer is : 14 is  greatest number of cups of yogurt Monica can buy.



3 0
2 years ago
Read 2 more answers
PLEASE HELP ME!!!!!!!!!
mihalych1998 [28]

Answer:

A) 24

Step-by-step explanation:

Total weight - loaded weight = space remaining in the trailer: 1050kg - 82kg = 968kg

space remaining ÷ the number of transport: 968 ÷ 40 = 24.2 OR 24

Hope it helps you

3 0
2 years ago
5.6 x 5.6 x 6.16 x 6.16
ivann1987 [24]

Answer:

5.6 x 5.6 x 6.16 x 6.16=1190

Step-by-step explanation:

5.6 x 5.6 x 6.16 x 6.16=1189.974016

Rounded up will be 1190.

8 0
3 years ago
HELP ASAPPPP !!!!!!!!!!!......
irina [24]

Answer:

just use a calculator

8 0
3 years ago
Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
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