The probability that a three shows on at least one of the dice is 11/36.
<h3>How to calculate the probability?</h3>
It should be noted that of probability means the likelihood of the occurence of an event.
The probability that a three shows on at least one of the dice will be:
= 11/36
This can be seen from the table that is attached.
The probability that the total is less than 8 will be:
= 21/36
= 7/12
Here, there are 21 places where the total is less than 8.
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Answer:
-2
Step-by-step explanation:
9+n/4= -15
cross multiply
9+4-15=n
13-15=n
n=-2
Answer:
Alternative C is the correct answer
Step-by-step explanation:
The first step is to determine the composite function;
![f[g(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D)
![f[g(x)]=cos[cot(x)]](https://tex.z-dn.net/?f=f%5Bg%28x%29%5D%3Dcos%5Bcot%28x%29%5D)
We then employ a graphing utility to determine the range and the domain of the new function.
The range is the set of y-values for which the function is defined. In this case it is;
![[-1,1]](https://tex.z-dn.net/?f=%5B-1%2C1%5D)
On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.
You have to simplify and then get x
Answer:
2
Step-by-step explanation:
f(x)=2x^2+9x-5
When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero
0=2x^2+9x-5
Factor the equation
0 = (2x+1) (x-5)
2*1
1*-5 = -5
2*-5 +1*1 = -9
This checks for the first last and middle terms so we factored correctly
Then using the zero product property
2x+1 = 0 and x-5 =0
2x = -1 x=5
x = -1/2 and x=5
This function crosses the x axis 2 times
