Which values from the given replacement set make up the solution set of the inequality?

Mathematics

2 answers:

VladimirAG [237]3 years ago

8 0

Answer: 5,6

Step-by-step explanation:

Substitute the numbers for n

il63 [147K]3 years ago

5 0

Answer: {5, 6}

Step-by-step explanation:

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Find the equation of the line that passes through the points (-4,-2) and (-3,5) in both point-slope form and

kaheart [24]

<h2>Answer:</h2>

First, we must determine the slope, then we find the y-intercept using slope formula and slope-intercept form.

<u>For slope:</u>

Slope (m) = 7

<u>For y-intercept:</u>

Y-intercept (b) = 26

Using this information, we can now create the equations for this line.

$y= 7x + 26\\\\y - 5 = 7(x + 3)$

Formulas:

Slope formula: <em>y₂ - y₁/x₂ - x₁</em>

Slope-intercept form: <em>y = mx + b</em>

Point-slope form: <em>y - y₁ = m(x - x₁)</em>

*Note: (x₁, y₁), (x₂, y₂) = <em>2 points on the line</em>

6 0

3 years ago

Help me!!! solve the inequality!! 8 ≤ x < 6

choli [55]

Hello! the answer to this inequality is no solutions, since there are no values of x for which this can be true.

4 0

3 years ago

State whether f is a function

Alenkinab [10]

<h2>Answer:</h2>

$y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function$

<h2>Step by step solution:</h2>

A function $f$ from a set $A$ to a set $B$ is a relation that assigns to each element $x$ in the set $A$ exactly one element $y$ in the set $B$ . The set $A$ is the domain (also called the set of inputs) of the function and the set $B$ contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function $f$ has an inverse function if and only if there is no any horizontal line that intersects the graph of $f$ at more than one point. So the function is called one-to-one. The graph of $f$ is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find $f^-{1}(x)$ :

$f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}$