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marta [7]
3 years ago
10

All rectangles have four right angles and opposite sides that are equal in length and parallel.

Mathematics
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

C. The bottom answer.

Step-by-step explanation:

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Pythagoras thereom ? help
Nutka1998 [239]

It looks like you have to do distance formula. It's basically this:

D = \sqrt{(y_{2}-y{1})^{2} + (x_{2}-x{1})^{2}   } (ignore the A, i dont know how to get rid of it sorry)

I would then plug in the points of A(1,7) and B(10,3).

D = \sqrt{(7-3)^2 + (10-1)^2  }

Then I would get the square root of 4^2 + 9^2

= square root of 16 + 81

= square root of 97

So the length of AB would be the square root of 97

4 0
4 years ago
A new car is purchased for $17,300 the value of the car dissipates at 9.25% per year will what will be the value of the car to t
mamaluj [8]

Answer:

17,300×9.25%= 160,025÷15=10,668

Step-by-step explanation:

that how much to purchased $10,668

3 0
3 years ago
Write two mixed numbers that are equal to 7.5.
Elenna [48]
7 1/2 and also 7 1/5
5 0
3 years ago
Read 2 more answers
What is the range for the following function? y=1/(x+2)+3
LUCKY_DIMON [66]

Answer:

\large \boxed{\text{C) }\{y: y \in \mathbb{R}, y \ne 3\} }

Step-by-step explanation:

The range is the spread of the y-values (minimum to maximum distance travelled).

The graph of your function is a hyperbola shifted two units left and three units up from the origin.

There is a vertical asymptote at x = -2, so y does not exist when x = -2.  However,

\displaystyle \lim_{x \rightarrow -{2}^{+}}f(x) = \lim_{x \rightarrow -{2}^{+}}\left (\dfrac{1}{x+2}+3 \right ) = 0 + 3 = 3\\\\\lim_{x \rightarrow -{2}^{-}}f(x) = \lim_{x \rightarrow -{2}^{-}}\left (\dfrac{1}{x+2}+3 \right ) = 0 + 3 = 3

Since the limit from either side is the same,

\displaystyle \lim_{x \rightarrow -{2}}f(x) = 3

The graph below shows the asymptotes of your function.

Thus. y can take any value  except 3.

In set builder notation, the range is  

\large \boxed{\mathbf{\{y: y \in \mathbb{R}, y \ne 3\} }}

4 0
3 years ago
A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver
Romashka [77]

Answer:

The time of a commercial airplane is 280 minutes

Step-by-step explanation:

Let

x -----> the speed of a commercial airplane

y ----> the speed of a jet plane

t -----> the time that a jet airplane takes  from Vancouver to Regina

we know that

The speed is equal to divide the distance by the time

y=2x ----> equation A

<u><em>The speed of a commercial airplane is equal to</em></u>

x=1,730/(t+140) ----> equation B

<u><em>The speed of a jet airplane is equal to</em></u>

y=1,730/t -----> equation C

substitute equation B and equation C in equation A

1,730/t=2(1,730/(t+140))

Solve for t

1/t=(2/(t+140))

t+140=2t

2t-t=140

t=140 minutes

therefore

The time of a commercial airplane is

t+140=140+140=280 minutes

6 0
4 years ago
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