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zubka84 [21]
4 years ago
6

The mean weight of a breed of yearling cattle is 11921192 pounds. Suppose that weights of all such animals can be described by t

he Normal model ​N(11921192​,7878​). ​a) How many standard deviations from the mean would a steer weighing 10001000 pounds​ be? ​b) Which would be more​ unusual, a steer weighing 10001000 ​pounds, or one weighing 12501250 ​pounds? ​
a) A steer weighing 10001000 pounds is 2.462.46 standard deviations below the mean. ​(Round to two decimal places as​ needed.) ​
b) The steer weighing 1000 pounds is more unusual.
Mathematics
1 answer:
Musya8 [376]4 years ago
4 0

Answer:

a) 2.46 standard deviations below the mean

b) The steer weighing 1000 pounds is more unusual.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1192, \sigma = 78

a) How many standard deviations from the mean would a steer weighing 1000 pounds​ be?

This is Z when X = 1000.

Z = \frac{X - \mu}{\sigma}

Z = \frac{1000 - 1192}{78}

Z = -2.46

Z = -2.46 is 2.46 standard deviations below the mean.

​b) Which would be more​ unusual, a steer weighing 1000 ​pounds, or one weighing 1250 ​pounds?

The higher the absolute value of the z-score, the more unusual the measure is.

X = 1000 pounds

Z = \frac{X - \mu}{\sigma}

Z = \frac{1000 - 1192}{78}

Z = -2.46

The absolute value of -2.46 is 2.46

X = 1250 pounds

Z = \frac{X - \mu}{\sigma}

Z = \frac{1250 - 1192}{78}

Z = 0.74

The absolute value of 0.74 is 0.74.

So the steer weighing 1000 pounds is more unusual.

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