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Andreyy89
3 years ago
15

How much less is 5/6 than 1​

Mathematics
2 answers:
Alexeev081 [22]3 years ago
8 0

Answer:

1 / 6

Step-by-step explanation:

1 - 5 / 6 = 1 / 6

because:

6 / 6 - 5 / 6 = 1 / 6

ycow [4]3 years ago
5 0

Answer:

1/6 or 0.16

Step-by-step explanation:

subtract 1 from 5/6 and it would be 1/6.

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On the grid, draw the graph of<br> y = 2x - 3<br> for values of x from -2 to 4<br> Q
Pie

Answer:

Plot these points:(-2,-7) (-1,-5) (0,-3) (1,-1) (2,1) (3,3) (4,5)

Step-by-step explanation:

You need to substitute your x values into the x of the equation y=2(3)-3 to find the y value...

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3 years ago
HELP ME PLEEEAASSEEE I SUCK AT MATH
irakobra [83]

Answer:

the answer is letter d

5 0
3 years ago
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Please help will give u brainliest pls help me​
masya89 [10]

Answer:

19

Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
Just learn this throughout a quick lesson, can someone help?
suter [353]

Answer:

The Pythagorean theorem is a^2+b^2=c^2 where c is the length of the longest, diagonal side (diagonal means opposite the right angle/small square).

Step-by-step explanation:

If you're looking for a short side (i.e. next to the right angle), square the longest one and subtract the square of the other known.

If you're looking for a long side (i.e. opposite the right angle), square both you know and add them together.

In both cases, take the Square Root with your calculator, or by trial and error, find a number that squares to make your current number.

[1] A square of the number x is x times x.

6 0
3 years ago
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