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mezya [45]
2 years ago
6

Select other ways to express 2:12

Mathematics
2 answers:
stiks02 [169]2 years ago
5 0

Answer:

12 after 2

Step-by-step explanation:

I got this correct on ed2020

balandron [24]2 years ago
3 0

Answer:

ratio

Step-by-step explanation:

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This is a 3 question thing! HELP!
romanna [79]

Answer:

Step-by-step explanation:

MR=2x-1. First equation

RP=9x+3 second equation

MP=MR+RP third equation

MP= 2x-1+9x+3 first equation plus second equation

MP=11x+2

MP=57

57=11x+2 replaced MP value

57-2=11x

55=11x

55/11=x

X=5

6 0
3 years ago
Help plz, no links.
Oksanka [162]

Answer:

1) g = -8 (one solution)

2) b = 0 (infinitely many solutions)

3) w = 5/6 (one solution)

4) c = 0 (infinitely many solutions)

Step-by-step explanation:

1) 1/2g -4 = 2g - 1/2g + 4

1/2g -2g +1/2 g = 8

-g = 8

2) 5.3-5.3 = 2.1b + b - 3.1b

0=0

3) 3/4w+ 3/4w = 10/4 - 5/4

3/2w = 5/4

w = (5/4) / (3/2)

w = 5/6

4) 5.7c + 3.2c - 7.8c - 1.1c = 1.5 - 1.5

0 = 0

7 0
2 years ago
If D-M-G, DM=2x , MG= x-2 , and DG= 7 , find x
Dmitrij [34]

Step-by-step explanation:

DG is the total measurement of the line. M is a point inbetween D & G

2x + x - 2 = 7

Simplify. Combine likke terms

(2x + x) - 2 = 7

3x - 2 = 7

Isolate the x. First, add 2 to both sides

3x - 2 (+2) = 7 (+2)

3x = 9

Isolate the x. Divide 3 from both sides

(3x)/3 = (9)/3

x = 9/3

x = 3

-------------------------------------------------------------------------------------------------

3 is your answer for x

--------------------------------------------------------------------------------------------------

~<em>Where the Good Way Lies, Hope Unfolds</em>

4 0
3 years ago
Initially a wheel rotating about a fixed axis at a constant angular deceleration of 0.5 rad/s 2 has an angular velocity of 0 rad
Zigmanuir [339]

Answer:

\theta = 5.83\ rad

Step-by-step explanation:

given,

angular deceleration, α = -0.5 rad/s²

final angular velocity,ω_f = 0 rad/s

angular position, θ = 6.1 rad

angular position at 3.9 s = ?

now, Calculating the initial angular speed

\omega_f^2 = \omega_i^2 + 2 \alpha \theta

0 = \omega_i^2 - 2\times 0.5\times 6.1

\omega_i = \sqrt{6.1}

\omega_i = 2.47\ rad/s

now, angular position calculation at t=3.9 s

\theta = \omega_i t + \dfrac{1}{2}\alpha t^2

\theta =2.47\times 3.9 - \dfrac{1}{2}\times 0.5\times 3.9^2

\theta = 5.83\ rad

Hence, the angular position of the wheel after 3.9 s is equal to 5.83 rad.

7 0
3 years ago
Compared to an exponential function y = b where b &gt; 0, a quadratic function grows: slower faster at the same rate sometimes f
Verizon [17]

Answer:

it's slower babe

6 0
3 years ago
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