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larisa86 [58]
3 years ago
5

Writing equation of the line that passes through the given points (16, -4) ; m= -3/4

Mathematics
2 answers:
Schach [20]3 years ago
8 0
I think it’s m= -1/16
makvit [3.9K]3 years ago
5 0

Answer:

y = -3/4 - 12

Step-by-step explanation:

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Help me please. either one is fine.
mestny [16]
7)
95+(3x+23)+(7x-4)+(9x-6)+90 = (5-2) x 180
x = 18

9)
41+(3x+6)+(7x-11)+62+(4x+7)+(6x-5) = 360
x = 13


6 0
3 years ago
What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 27 − x^2? show your
LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given curve is

y=27-x^2

We need to find the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y=27-x^2.

Let the vertex in quadrant I be (x,y), then the vertex in quadrant II is (-x,y) .

Length of the rectangle = 2x

Width of the rectangle = y

Area of a rectangle is

Area=Length\times width

Area=2x\times y

Substitute the value of y from the given equation.

Area=2x(27-x^2)

A=54x-2x^3      .... (1)

Differentiate with respect to x.

\frac{dA}{dx}=54-6x^2

Equate \frac{dA}{dx}=0, to find the critical points.

0=54-6x^2

6x^2=54

Divide both sides by 6.

x^2=9

x=\pm 3

The value of x can not be negative because side length can not be negative.

Substitute x=3 in equation (1).

A=54(3)-2(3)^3

A=162-54

A=108

The area of the largest rectangle is 108 square units.

Therefore, the correct option is B.

7 0
3 years ago
two wheels are rolled simultaneously. The radius of the smaller wheel is r feet and the radius of the larger wheel 2r feet. If b
Nuetrik [128]
The circumference of a circle is C=2πR, where R is the radius of the circle and π≈3.14.

So if we open the circumference of the circle into a straight line segment, the length of this segment is C=2πR≈2*3.14*R=6.28R

4 rotations mean 4 circumferences that is 4 segments of length 6.28R, 
which makes a linear distance of 4*6.28R=25.12R


i: the radius of the smaller wheel is R=r, thus it covers a distance of 25.12r feet

ii: the radius of the smaller wheel is R=2r, thus it covers a distance of  25.12*2r=50.24r (feet)

50.24r is twice 25.12r, thus the larger wheel traveled Twice the distance of the smaller one.


Answer: the larger covered twice the distance of the smaller.
6 0
3 years ago
the triangle below is 45-45-90 determine the value of x and y your awsner must be in simplest radical form you cannot use sine c
Alexeev081 [22]

The diagram can be redrawn as,

The value of x and y can be determined as,

\begin{gathered} \tan C=\frac{AB}{BC} \\ \tan 45^{\circ}=\frac{x}{7\sqrt[]{2}} \\ x=7\sqrt[]{2} \end{gathered}\begin{gathered} \cos C=\frac{BC}{AC} \\ \cos 45^{\circ}=\frac{7\sqrt[]{2}}{y} \\ y=14 \end{gathered}

Thus, option (D) is the correct solution.

4 0
1 year ago
Simplify completely x^2+7x-30/x+10
marta [7]

Answer:

(x-3)

Step-by-step explanation:

we have

\frac{x^{2}+7x-30}{x+10}

step 1

Simplify the numerator

Complete the square

Equate the equation to zero

x^{2}+7x-30=0

x^{2}+7x=30

x^{2}+7x+3.5^{2}=30+3.5^{2}

x^{2}+7x+12.25=42.25

Rewrite as perfect squares

(x+3.5)^{2}=42.25

Take square root both sides

(x+3.5)=(+/-)6.5

x=-3.5(+/-)6.5

x=-3.5(+)6.5=3

x=-3.5(-)6.5=-10

therefore

x^{2}+7x-30=(x-3)(x+10)

substitute in the numerator

\frac{x^{2}+7x-30}{x+10}=\frac{(x-3)(x+10)}{x+10}=x-3

8 0
4 years ago
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