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3 years ago

Writing equation of the line that passes through the given points (16, -4) ; m= -3/4

Mathematics

2 answers:

Schach [20]3 years ago

8 0

I think it’s m= -1/16

makvit [3.9K]3 years ago

5 0

Answer:

y = -3/4 - 12

Step-by-step explanation:

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A publisher reports that 42%42% of their readers own a particular make of car. A marketing executive wants to test the claim tha

shepuryov [24]

Answer:

$z=\frac{0.35 -0.42}{\sqrt{\frac{0.42(1-0.42)}{250}}}=-2.24$

Step-by-step explanation:

Data given and notation

n=250 represent the random sample taken

$\hat p=0.35$ estimated proportion of readers owned a particular make of car

$p_o=0.42$ is the value that we want to test

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that that the percentage is actually different from the reported percentage.:

Null hypothesis: $p=0.42$

Alternative hypothesis: $p \neq 0.42$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.35 -0.42}{\sqrt{\frac{0.42(1-0.42)}{250}}}=-2.24$

6 0

3 years ago

480 = x+5y<br><br><br> Please tell me how to solve this....

Ksenya-84 [330]

You would first divide by 5y which equals 96, so x equals 96. Hope this helped! :)

480=x+5y
480/5y=x+5y/5y
96=x

4 0

3 years ago

I need some Help please :)

pychu [463]

I think it’s the last one

5 0

4 years ago

1. A breakfast cereal is made of oats, nuts, and raisins. The advertisements boast that 25% of the cereal in each box is almonds

kotykmax [81]

Answer:

Step-by-step explanation:

1) The advertisements boast that 25% of the cereal in each box is almonds. It means that the percentage of the other cereals in the box is 100 - 25= 75%

Therefore, the portion of each box that is not almonds is 75/100 = 0.75

2) The advertisements boast that 25% of the cereal in each box is almonds. If each box contains 12 cups of cereal, then the number of cups of almonds in each box is

25/100 × 12 = 3 cups

3) if each box contains 12 cups of cereal, and 4 cups are oats, then the percentage of each box that is oats is

4/12 × 100 = 33.33%

4 0

3 years ago

In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track

Aloiza [94]

Answer:

Approximately $0.31\; \rm m$ , assuming that $g = 9.81\; \rm N \cdot kg^{-1}$ .

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

$\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned}$ .

Weight of the slide:

$\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}$ .

Normal force between the sled and the slope:

$\begin{aligned}F_{\rm N} &= W\cdot \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}$ .

Calculate the kinetic friction between the sled and the slope:

$\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}$ .

Assume that the sled and its passenger has reached a height of $h$ meters relative to the base of the slope.

Gain in gravitational potential energy:

$\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}$ .

Distance travelled along the slope:

$\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}$ .

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

$\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}$ .

In other words, the sled and its passenger would have lost (approximately) $((137 + 68.1)\, h)\; {\rm J}$ of energy when it is at a height of $h\; {\rm m}$ .

The initial amount of energy that the sled and its passenger possessed was $\text{KE} = 63\; {\rm J}$ . All that much energy would have been converted when the sled is at its maximum height. Therefore, when $h\; {\rm m}$ is the maximum height of the sled, the following equation would hold.

$((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}$ .

Solve for $h$ :

$(137 + 68.1)\, h = 63$ .

$\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}$ .

Therefore, the maximum height that this sled would reach would be approximately $0.31\; \rm m$ .

7 0

3 years ago