The solution is indeed accurate.
Here's a rough graph haha
the graph has a factor of 4/1 (considered the "slope"), and the vertex is translated 2 units to the right (whatever is in the | lines | has the negative/positive flipped), and 6 units down.
Answer:
Option 2 50 ≤ s ≤ 100
Option 5 She could deposit $50
Option 6 She could deposit $75
Step-by-step explanation:
Let
s -----> amount of money Layla deposit into a saving account
we know that
25%=25/100=0.25
50%=50/100=0.50
so
-----> 
-----> 
The compound inequality is

<em>Verify each case</em>
case 1) 25 ≤ s ≤ 50
The statement is false
see the procedure
case 2) 50 ≤ s ≤ 100
<u>The statement is True</u>
see the procedure
case 3) s ≤ 25 or s ≥ 50
The statement is false
Because is s ≤ 100 and s ≥ 50
case 4) s ≤ 50 or s ≥ 100
The statement is false
Because is s ≤ 100 and s ≥ 50
case 5) She could deposit $50
<u>The statement is true</u>
Because the value of s satisfy the compound inequality 
case 6) She could deposit $75
<u>The statement is true</u>
Because the value of s satisfy the compound inequality 
You need to plot each line and see where they intersect.
Line 1: y = x+2
Plot the y-intercept (0,2) because of the +2 in the equation.
From (0,2), count "up 1, right 1" to get a second point, because the slope is 1.
From that new point, repeat the "up 1, right 1" to plot a third point.
Connect the dots to make your line.
Line 2: y = -1/3 x - 2
Repeat the same process, using the the y-intercept and slope for this line.
Then identify where they intersect.
1/7 is the answer. 4/28 = 1/7 but in the lowest term