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inna [77]
3 years ago
14

Which number line represents the solution of x + 3 > 2?

Mathematics
1 answer:
Ghella [55]3 years ago
6 0

Answer:

x > -1

(-1, infinity)

Step-by-step explanation:

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What is 114/228 simplified?​
aalyn [17]

Answer:

1/2

Step-by-step explanation:

8 0
3 years ago
Given A = {1, 3, 5}, B = {2, 4, 6} and C={1, 2, 3, 4, 5, 6}, then A ∪ (B ∩ C)
Serggg [28]
B ∩ C is an intersection, which means only values that are present in both B and C are picked. So...
B ∩ C = {2, 4, 6}
A ∪ (B ∩ C) is a union, which means you combine all values, but discard duplicates. So...
A ∪ (B ∩ C) = {1, 2, 3, 4, 5, 6}
8 0
3 years ago
Read 2 more answers
Simplify <br><br> -√125^3<br><br> Please help
klio [65]
-(5v5)^3 (use exponent rules)
-125x5v5 (calculate the product)
=-625v5 (pretend the v is a square root sign)

3 0
3 years ago
This is the question​
Maurinko [17]
I dont see a question.
7 0
3 years ago
Cos(−θ)=√3/3, sinθ&lt;0
Delicious77 [7]

Answer:

\sin\theta=-\frac{\sqrt{6}}{3}


Step-by-step explanation:

The given trigonometric equation is \cos(-\theta)=\frac{\sqrt{3} }{3}.

We can either use the Pythagorean identity or the right angle triangle  to solve for \sin\theta.

According to the Pythagorean identity,

\cos^2\theta+\sin^2\theta=1


Recall that, the cosine function is an even function, therefore

\cos(-\theta)=\cos(\theta)


\Rightarrow \cos(\theta)=\frac{\sqrt{3} }{3}.

We substitute this value in to the above Pythagorean identity to get;


(\frac{\sqrt{3}}{3})^2+\sin^2\theta=1


\Rightarrow \frac{3}{9}+\sin^2\theta=1


\Rightarrow \sin^2\theta=1-\frac{3}{9}


\Rightarrow \sin^2\theta=\frac{6}{9}


\Rightarrow \sin\theta=\pm \sqrt{\frac{6}{9}}


\Rightarrow \sin\theta=\pm \frac{\sqrt{6}}{3}


But we were given that,

\sin\theta\:, so we choose the negative value.

\Rightarrow \sin\theta=-\frac{\sqrt{6}}{3}


The correct answer is B







7 0
4 years ago
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