$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
Replace a and b with their given values:
(2(3/5) -1/3) / -6.75/15
2 x 3/5 = 6/5
6/5 - 1/3 = 18/15 - 5/15 = 13/15
13/15 / -6.75/15 = 13/15 x 15/-6.75 = (13 x 15) / (15 x -6.75) = 195/-101.25 = -1 25/27
Answer: -1 and 25/27
Answer:

Step-by-step explanation:
In every right triangle, a leg is given by the multiplication of the sine of its opposite angle and the hypothenuse.
In this case, the opposite angle of x is 15°, and the hypothenuse is 300. So, we have

Answer:
5 seconds
Step-by-step explanation:
hope it helps
correct me if i'm wrong