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kotegsom [21]
3 years ago
8

Which rectangular prism will have the largest volume?

Mathematics
2 answers:
Sophie [7]3 years ago
4 0
The 1st on because its volume is equal to 108 which is the highest of the four
krek1111 [17]3 years ago
3 0
I wouldn’t really know
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Please quickly help me!!
Ainat [17]

Look at the picture.

Answer:

\angle ADB\cong\angle ACB\\\\\angle DAC\cong\angle DBC

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4 years ago
PLS HELP!<br><br> x^2 + 5x +5
AVprozaik [17]

You can't simplify this problem any further because there are no more like terms

5 0
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Whats three to the forth power
aalyn [17]

Answer:

1514

Step-by-step explanation:

3 0
3 years ago
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. Complete the congruence statement.
dexar [7]

Answer: angle N

Step-by-step explanation:

The order of the triangle names HAS to indicate which angles are congruent. First letters are congruent (D and M), second letters are congruent (E and N), and third are congruent (F and O). Also, the diagram shows that the triangles are reflections of each other. reflect one triangle onto the other, and you see that E and N overlap.

7 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
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