Formula- A = π r²
a= area
r= radius
diameter of the circle- 3.75 x 2 = 7.5
hope this helps :)
Let's see what's the domain and range for the given function ~
![\qquad \tt \dashrightarrow \:domain \in [ -5 , 4 ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3Adomain%20%5Cin%20%5B%20-5%20%2C%204%20%5D%20)
or
Because domain = all values of x between its maximum (4) and minimum (-5) value [ including them ]
![\qquad \tt \dashrightarrow \:range \in[ -4 , 9 ]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Cdashrightarrow%20%5C%3Arange%20%5Cin%5B%20-4%20%2C%209%20%5D)
or
Because range = all values of y between its maximum (9) and minimum (-4) value [ including them ]
Answer:
m∠QPR = 35° m∠QPM =40° m∠PRS = 30°
Step-by-step explanation:
ΔPRQ is a right triangle with right angle at R. So m∠QPR = 90 - 55 = 35
ΔQPM is a right triangle with right angle at M. So m∠QPM = 90 - 40 = 40
Arc RQ = 2(35) = 70 and arc SR = 2(25) = 50.
So arc PS = 180 - (arc RQ + arc SR) = 180 - (70 + 50) = 180 - 120 = 60
Now arc PS is the intercepted arc for ∠PRS.
Therefore, m∠PRS = 60/2 = 30
I used the fact that an inscribed angle has a measure 1/2 the measure of the intercepted arc several times. Also, I used the fact that the acute angles of a right triangle are complementary. And, finally I used the fact that an inscribed angle in a semicircle is a right angle.
I hope this helped.
Answer:
The answer would be 3*5*50 which equals 750 kilometers.
Step-by-step explanation:
This equals to 2/(1/5)+(1/5)/2.
=2 x 5+1/5 x 1/2
=10+1/10
=10 1/10 <---- This is mixed fraction, since you didn't want decimals.
