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Dmitrij [34]
3 years ago
6

PLS HELP I WILL GIVE BRAINLIEST

Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

there's no question

Step-by-step explanation:

....

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Read 2 more answers
Solve for x in the equation x^2- 10x+ 25=35
DIA [1.3K]

Answer:

<h3>x = 5  +  \sqrt{35}  \:  \:  \:or \:  \:  \: x = 5 -  \sqrt{35}  \\</h3>

Step-by-step explanation:

x² - 10x + 25 = 35

Move 35 to the left side of the equation

That's

x² - 10x + 25 - 35 = 0

x ² - 10x - 10 = 0

Using the quadratic formula solve the equation

That's

<h3>x =  \frac{ - b\pm \sqrt{ {b}^{2} - 4ac } }{2a}</h3>

From the question

a = 1 , b = - 10 , c = - 10

Substitute the values into the above formula and solve

That's

x =  \frac{ -  - 10\pm \sqrt{( { - 10})^{2} - 4(1)( - 10) } }{2(1)}  \\  =  \frac{10\pm \sqrt{100 + 40} }{2}  \\  =  \frac{10\pm \sqrt{140} }{2}  \\  =  \frac{10\pm2 \sqrt{35} }{2}  \\  =  \frac{10}{2} \pm \frac{2 \sqrt{35} }{2}  \\  = 5\pm \sqrt{35}

We have the final answer as

<h3>x = 5  +  \sqrt{35}  \:  \:  \:or \:  \:  \: x = 5 -  \sqrt{35}  \\</h3>

Hope this helps you

7 0
3 years ago
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