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3 years ago

It's making me write 20 characters right here.

Mathematics

2 answers:

Anestetic [448]3 years ago

6 0

the answer is 20% because well duh

GrogVix [38]3 years ago

4 0

Answer:

18.5%

Step-by-step explanation:

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Leslie bought an

Evgen [1.6K]

Answer:

$1.00

hopefuly this helped if not let me know!

5 0

3 years ago

Read 2 more answers

Jacob leaves his summer cottage and drives home. After

krok68 [10]

Answer:

A linear relationship can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If this line passes through the points (a, b) and (c, d) then the slope can be written as:

a = (a - c)/(b - d)

Here y will represent the distance between Jacob and his house, and the variable x represents the time that he has ben driving.

In this case, we know that after driving for 5 hours, he is 112km from home.

Then we can write this point as (5h, 112km)

We also know that after 7 hours he is 15km from home.

Then we can write this point as (7h, 15km)

Then the slope of this function will be:

a = (15km - 112km)/(7h - 5h) = -48.5 km/h

Then the equation is:

y = -(48.5 km/h)*x + b

To find the value of b, we can replace the values of one of the points, for example in the point (7h, 15km)

This means that we need to replace x by 12h, and y by 15km, then we get:

15km = -( 48.5 km/h)*7h + b

15km + ( 48.5 km/h)*7h = b = 354.5 km

then the equation will be:

y = (-48.5 km/h)*x + 354.5 km

Now we want to answer: How long had Jacob been driving when he was 209 km from home?

Then we need to only replace y by 209km, and solve for x:

209km = (-48.5 km/h)*x + 354.5 km

209km - 354.5 km = (-48.5 km/h)*x

-145.5km = (-48.5 km/h)*x

-145.5km/( -48.5 km/h) = x = 3h

So he is 209km away from his home after driving for 3 hours.

6 0

3 years ago

The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 5 minutes and a stand

erastovalidia [21]

Answer:

$z=0.524$

And if we solve for a we got

$a=5 +0.524*2=6.048 \approx 6.05 min$

Step-by-step explanation:

Let X the random variable that represent the lenght time it takes to find a parking space at 9AM of a population, and for this case we know the distribution for X is given by:

$X \sim N(5,2)$

Where $\mu=5$ and $\sigma=2$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.3$ (a)

$P(X$ (b)

As we can see on the figure attached the z value that satisfy the condition with 0.7 of the area on the left and 0.3 of the area on the right it's z=0.524

If we use condition (b) from previous we have this:

$P(X$