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3 years ago

Determine whether the scenario involves independent or dependent events.

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

6 0

Answer:

independence is the correct answer

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oil is leaking out of a tank. the depth of oil in the tank for 60 seconds is shown below. use the graph to work out the rate of

FrozenT [24]

Answer:

Step-by-step explanation:

draw a tangent starting from (0,80) and touches at (10,60)... Example attached if needed... Good Luck! ;)

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4 years ago

55/78= what as a decimal?

Alinara [238K]

55/78
= (55*(50/39)) / (78*(50/39))
= 70.(512820)/ 100
= 0.7(051282)

The final answer is 0.7(051282)~

5 0

3 years ago

I just need some quick help with this. Distributive properties aren't my best section.

Anni [7]

In this case u can’t use the distributive property. U just multiple whats in the parenthesis (39•5)=195 and that’s ur answer.
Let’s say if the problem said 5(2+1) u can’t use the distributive property bc u have to do what’s in the parentheses first. 5(3)=15
But If u had a problem like 2(4x+6) then u can use the distributive property. This is bc u can’t add 4x+6 bc they aren’t like terms. So u multiple the 2 by 4x which is 8x and the 2 by 6 which is 12 then ur answer would be : 8x+12

4 0

3 years ago

A random sample of 401 student were recent survey regarding their class standing freshmen software junior senior and their major

SOVA2 [1]

the Solution

$Pr(\text{STEM)}=\frac{158}{401}=0.394$ $Pr(\text{Sophomore)}=\frac{87}{401}=0.217$ $Pr(sophomore|Non-stem)=\frac{68}{401}=0.170$ $Pr(\text{sophomore and Non-stem)=}\frac{87}{401}\times\frac{243}{401}=\frac{21141}{160801}=0.1315$

To ascertain whether Sophomore and Non-stem are dependent, we have to test the following:

$\begin{gathered} If\text{ Pr(sophomore or Non-stem) = Pr(sophomore and Non-stem),} \\ \text{then we conclude that both events are Independent,} \\ \text{otherwise, they are dependent.} \end{gathered}$ $\begin{gathered} Pr(\text{sophomore or Non-stem)=Pr(sophomore)+Pr(Non-stem)} \\ -Pr(\text{sophomore and Non-stem)} \end{gathered}$ $Pr(\text{Sophomore or Non-stem)=}\frac{87}{401}+\frac{243}{401}-(\frac{87}{401}\times\frac{234}{401})$ $=\frac{330}{401}-\frac{21141}{160801}=0.82294-0.13147=0.69147$

Cleary, we have that sophomore and non-stem events are dependent events since 0.69147 is not the same as 0.13147.

4 0

1 year ago

Solve for P<br> 5/6p + 1= 3/4p -4

trapecia [35]

Hii so p is equal to -60

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3 years ago

Read 2 more answers