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mel-nik [20]
3 years ago
14

What is the equation of a circle with its center at (−6,−3) and a radius of 12?

Mathematics
2 answers:
Marat540 [252]3 years ago
8 0

Answer:

x² + y² + 12x +6y - 99 = 0

Step-by-step explanation:

<u>G</u><u>iven </u><u>:</u>

  • Centre = (-6,-3)
  • Radius = 12 ,

<u>Using</u><u> </u><u>the </u><u>Standard</u><u> equation</u><u> of</u><u> </u><u>circle</u><u> </u><u>,</u><u> </u>

  • ( x - h)² + (y-k)² = r²
  • ( x +6)² + (y+3)² = 12²
  • x² + 36 + 12x + y² + 9 + 6y = 144
  • x² + y² + 12x + 6y +45-144 = 0
  • x² + y² + 12x +6y - 99 = 0
zavuch27 [327]3 years ago
7 0

Answer:

(x+6)^2 + ( y +3)^2 = 144

Step-by-step explanation:

The equation of a circle is given by

(x-h)^2 +(y-k)^2 = r^2  where (h,k) is the center and r is the radius

(x- -6)^2 + ( y - -3)^2 = 12^2

(x+6)^2 + ( y +3)^2 = 144

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