Log4(x^2+1)=log4(-2x)

Bill's recipe for onion soup call for 4.0lb of thinly sliced onions. If an onion has an average mass of 115g, how many onions do

musickatia [10]

Answer:

1. $16\ onions$

2. $4,040.91\ kg$

Step-by-step explanation:

1. You know that the average mass of an onion is 115 grams and Bill needs 4.0 pounds.

Then, since $1\ lb=453.592\ g$ , we can make the following conversion:

$(4.0\ lb)(\frac{453.592\ g}{1\ lb})=1,814.37\ g$

Then, the number of onions Bill needs is:

$(1,814.37\ g)(\frac{1\ onion}{115\ g})=15.77\ onions$ ≈ $16\ onions$

2. Since $1\ kg=2.20462\ lb$ , we can make the following conversion:

$(11\ lb)(\frac{1\ kg}{2.20462\ lb})=4.98\ kg$

Knowing that all the potatoes sold today at the store bring in $1,420 and 4.98 kilograms of potatoes is $1.75, we can calculate the amount of kilograms the grocery shoppers bought:

$(\$1,420)(\frac{4.98\ kg}{\$1.75})=4,040.91\ kg$

6 0

2 years ago

An Ontario lottery has the following structure, the first person drawn from the names wins $15 000. Each subsequent person drawn

elixir [45]

The first four terms are : 15000, 14850, 14700, 14550
a = 15000 ; d = -150
The explicit formula is : $a_{n} = - 150n \: + 15150$

The first term of the sequence, a = 15,000

Each subsequent winner gets $150 less

Hence, the common difference, d = - $150

The first four terms :

First term, a1 = $15000

Second term, a2 = a - d = $15000 - $150 = $14850

Third term, a3 = a2 - d = $14850 - $150 = $14700

Fourth term, a4 = a3 - d = $14700 - $150 = $14550

a, for the sequence is the first term = $15000

d, for the sequence is the common $150 (difference between successive wins).

Explicit formula for the general term :

$a_{n} \: = nd \: + c$

For n = 1

$15000 = 1( - 150) + c$

$15000 = - 150 + c$

$c = 15150$

Hence, the explicit formula for the nth term is :

$a_{n} \: = - 150n \: + 15150$

Learn more : brainly.com/question/12006170

3 0

2 years ago

1. Which equation is the inverse of y = 2x2 + 25 ?

Alborosie

Imma go with F just because I think it’s right

3 0

3 years ago

Need this answered please!!

Paraphin [41]

Their 3 angles are equal (64,26,90)

Hope this will help...

Please mark as brainliest

6 0

2 years ago

Determine the values of the variables in isosceles trapezoid CHLE below.

Alex73 [517]

Answer:

The values of variables x and m are 11 and 17

Step-by-step explanation:

The question has missing details as the diagram of the trapezoid isn't attached.

(See attachment).

Given that trapezoid CHLE is isosceles then the angles at the base area equal (4x)

And

The angles at the top are also equal

8m = 11x + 15

At this point, the four angles in the trapezoid are 8m, 11x + 15, 4x and 4x..

The sum of interior= 360

So,

11x + 15 + 8m + 4x + 4x = 360

Collect like terms

11x + 4x + 4x + 8m = 360 - 15

19x + 8m = 345

Substitute 11x + 15 for 8m

19x + 11x + 15 = 345

30x + 15 = 345

30x = 345 - 15

30x = 330

Divide through by 30

30x/30 = 330/30

x = 11

Recall that 8m = 11x + 15;

8m = 11(11) + 15

8m = 121 + 15

8m = 136

Divide through by 8

8m/8 = 136/8

m = 17

Hence, the values of variables x and m are 11 and 17

7 0

2 years ago

Log4(x^2+1)=log4(-2x)​

Log4(x^2+1)=log4(-2x)