Answer:
,
Step-by-step explanation:
First, simplify the denominator. Ignore the numerator for the time being.
To simplify it, we need to multiply each numerator by the opposite's denominator so we can add them together:
![\frac{1(x+2)}{x(x+2)} + \frac{1(x)}{x(x+2)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%28x%2B2%29%7D%7Bx%28x%2B2%29%7D%20%2B%20%5Cfrac%7B1%28x%29%7D%7Bx%28x%2B2%29%7D)
You can simplify this to get
![\frac{2x + 2}{x^2 + 2x}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%20%2B%202%7D%7Bx%5E2%20%2B%202x%7D)
So this is your denominator when simplified. To simplify the entire fraction, we need to divide it. We can do this by reversing the numerator and denominator of the bottom fraction to
. This is done when dividing fractions by fractions.
Now, it should look something like this:
![\frac{x}{x+2} *\frac{x^2+2x}{2x+2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx%2B2%7D%20%2A%5Cfrac%7Bx%5E2%2B2x%7D%7B2x%2B2%7D)
This is equal to
![\frac{x^2(x+2)}{(x+2)(2x+2)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%28x%2B2%29%7D%7B%28x%2B2%29%282x%2B2%29%7D)
Seeing as there is a (x+2) on both the numerator and the denominator, you can eliminate it from the equation to get this:
![\frac{x^2}{2(x+1)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%7D%7B2%28x%2B1%29%7D)
The answer for your question is number 2
The answer is 0 > 34, or No Solution to be exact. use the picture above as the appropriate symbol for No Solution.
The events are dependent.
When the first card is not replaced, you change the probability of the second card. At the very least, you have changed the total number of cards to draw from.