The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
X = 3 y = 4
so answer is 4
If R is the midpoint of PS, then PR = RS -- (1)
Also, PR + RS = PS -- (2)
__________________
PR + RS = PS
7x + 23 + 13x - 19 = PS
__________________
Now, PR = PS
7x + 23 = 13x - 19
7x - 13x = -19 - 23
-6x = -42
x = -42/-6
x = 7
__________________
PS = 7x + 23 + 13x - 19
PS = 7(7) + 23 + 13(7) - 19
PS = 49 + 23 + 91 - 19
<u>PS </u><u>=</u><u> </u><u>1</u><u>4</u><u>4</u><u> </u>
Hope it helps!
꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂
Answer: y is 40 x is 60
Step-by-step explanation:
3x + 7 > 4x + 3
subtract 3x from both sides
7 > x + 3
7 - 3 > x
x < 4