Answer:
60 inches long are the sides of the pillars.
Step-by-step explanation:
Given : A small bridge sits atop four cube shaped pillars that all have the same volume. the combined volume of the four pillars is 500 ft cubed.
To find : How many inches long are the sides of the pillars?
Solution :
Refer the attached picture below for Clarence of question.
The volume of the cube is 
Where, a is the side.
The combined volume of the four pillars is 500 ft cubed.
The volume of each cube is given by,
Substitute in the formula to get the side,
![a=\sqrt[3]{125}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7B125%7D)
We know, 1 feet = 12 inches
So, 5 feet =
inches
Therefore, 60 inches long are the sides of the pillars.
Answer:
24.96%
Step-by-step explanation:
HOPE I WAS FAST ENOUGH
<h2>19.</h2><h3>Given</h3>
- window width and height are in proportion to building width and height
- window width and height are 11 in and 18 in, respectively
- building height is 108 ft
<h3>Find</h3>
<h3>Solution</h3>
The proportional relation can be written as
... (building width)/(building height) = (window width)/(window height)
Multiplying by (building height) gives
... (building width) = (building heigh) × (window width)/(window height)
... (building width) = 108 ft × (11 in)/(18 in)
... building width = 66 ft
<h2>21.</h2><h3>Given</h3>
- map distance = 6.75 in
- map scale = 1.5 in : 5 mi
<h3>Find</h3>
<h3>Solution</h3>
The distances are in proportion, so
... (map distance) : (actual distance) = 1.5 in : 5 mi
Multiplying by (5 mi)/(1.5 in)×(actual distance), we have
... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi
First seperate the irregular shape into 2 regular shapes, by splitting the yellow part down the middle horizontally we get 2 obtuse triangles. Then we just need to find the area of both, to do this we just need base and height, this is 24 in base 15 in height
the area of each half is 180 square inches
180 + 180 = 360
the answer is A 360 square inches
That would be tan
(1-cos)(1+cos)=1-cos² which equals to sin²
√sin²/cos²= sin/cos which equals to tan
