Let's say x = full price tickets
Let's say y = student tickets
We can write two equations:
From "585 tickets were sold" we can make the equation:
x + y = 585
And from "Full-price ticket is $2.50 and student ticket is $1.75 and total receipts is $1,217.25"...we can make the equation:
2.50x + 1.75y = 1,217.25
So now we can use substitution to find our answer...since we only have to find how many student tickets...we will solve the first equation for x so we can plug that into the 2nd equation to solve for y.
x + y = 585
x + y - y = 585 - y
x = 585 - y
Now we plug that into our 2nd equation: 2.50 (585 - y) + 1.75y = 1217.25
Distribute your 2.50
1462.5 - 2.50y + 1.75y = 1217.25
Add the y's: 1462.5 - 0.75y = 1217.25
Subtract 1462.5 from both sides:
1462.5 - 0.75y - 1462.5= 1217.25 - 1462.5
-0.75y = -245.25
Divide both sides by -0.75:
y = -245.25/-0.75
y = 327
There were 327 student tickets :)
Answer:
y + 4 = 4(x-4)
Step-by-step explanation:
Use the point slope form of a line to write the equation by substituting m = 4 and the point (4,-4).
For part B
the fixed cost is 500 dollars because it is a set inital amount, the varibale cost is .15 because it is the cost dependent on something else (per indicated variable part)
y=.15x+500
.15 cents per flyer, add 500 because that is the set amount it costs to even create the flyer
Plug in 500 for the equation
y=.15(500)+500
y=75+500
y=575
for part a
b=ka for direct variations so the direct one is C - two items directly multiplied
y=mx+b for partial variation so its A,D - basically the equation of a line
A is neither - shows neither of these relationships
Answer:
No
Step-by-step explanation:
There's no such thing as -sin
Answer:
plz like and rate
Step-by-step explanation:
Find the nth term of this number sequence.
2 8 14 20 26
Again write the numbers 1 to 5 above the numbers in the sequence, and leave a spare line again.
n 1 2 3 4 5 (1st row)
(2nd row)
2 8 14 20 26 (3rd row)
Since the sequence is going up by 6, write down your multiples of 6 on the 2nd row.
n 1 2 3 4 5 (1st row)
6n 6 12 18 24 30 (2nd row)
2 8 14 20 26 (3rd row)
Now, to get the numbers in the 3rd row from the 2nd row take off 4.
So, to get from the position numbers (n) to the numbers in the sequence you have to times the position numbers by 6 and take off 4.
Therefore, the nth term = 6n – 4
