Don't you mean "the sum of the squares ..."?
The sum of the squares of two consecutive whole numbers is 25. Find the numbers. Let the first be represented by x and the second by x+1.
Then x^2+(x+1)^2=25. Expanding, x^2+x^2+2x+1=25.
Rewriting this as a quadratic equation in standard form,
2x^2+2x+1=25, or 2x^2+2x-24=0. Simplifying, x^2+x-12=0.
Factoring, (x-3)(x+4)=0. Solving for x: x-3=0, so x=3; x+4=0, so x=-4.
Choose the positive x value: x=3. Then the next consecutive number is 2+1=3+1=4.
Check: Does 3^2 + 4^2 = 5^2 = 25? Yes.
The numbers are 3 and 4.
The discriminant is the part under the sqrt in the quadratic formula
for ax²+bx+c, the discriminant is b²-4ac
if the discriminant is
less than 0, then there are non-real roots
equal to 0, then there is a double root
greater than 0, then there are 2 real roots (may be rational or irrational)
so
1x²-5x+7
b²-4ac=(-5)²-4(1)(7)=25-28=-3
less than 0 so it is non real roots
answer is D
I just wanted to apologize to y’all for asking you fishsmaple
(01)
- 0.9 , 323.5
- 2.156 , 4.777 , 87.669
(02)
- Tenths
- Tens
- Thousandths
- Hundredths
- Ones
- Ten Thousandths
(03) Yes, The xavier is correct.
8.953 > 8
8.953 < 9
8.953 is bigger than 8 and smaller than 9.
9.000 - 8.953 = 0.047
(04)
- 10
- 10
- 1000
- 1000
- 1000
- 100
- 1000
- 100
- 10
(05)
- 0.6
- 8.3
- 2.5
- 9.2
- 12.9
- 0.1
(06)
- 0.6
- 7
- 0.7
- 2
- 36.8
- 6.1 & 18.3
(07)
- 2.1
- 2.3
- 0.7
- 2.8
- 1.3
(08)
- 4.13
- 2.31
- 1.21
- 3.11
- 9.01
<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>
_♡_mashi_♡_
