The information is in the picture

An empty shipping box weighs 250 grams. The box is then filled with T-shirts. Each T-shirt weighs 132.5 grams. The equation re

just olya [345]

Answer:

Equation:

250 + 132.5y = x

Solution for solving for x:

x = 250 + 132.5y

Solution for solving for y:

y = (x - 250)/132.5

In this situation, the solutions mean that the equation is linear or first grade because the solutions can be calculated in any of the following four forms:

1. Adding the same number to both sides

2. Subtracting the same number from both sides

3. Multiplying both sides by the same number

4. Dividing both sides by the same number

Completing the question and statement correctly:

The equation represents the relationship between the quantities in this situation, where x is the weight, in grams, of the filled box and y the number of shirts in the box.

Step-by-step explanation:

1. Let's review all the information provided to us to answer the question correctly:

Weight of an empty box = 250 grams

Weight of each T-shirt = 132.5 grams

2. Name two possible solutions to the equation that represent the relationship between the quantities in this situation, where x is the weight, in grams, of the filled box and y the number of shirts in the box. What do the solutions mean in this situation?

x = weight, in grams, of the filled box

y = number of shirts in the box

Equation:

250 + 132.5y = x

Solution for solving for x:

x = 250 + 132.5y

Solution for solving for y:

y = (x - 250)/132.5

In this situation, the solutions mean that the equation is linear or first grade because the solutions can be calculated in any of the following four forms:

1. Adding the same number to both sides

2. Subtracting the same number from both sides

3. Multiplying both sides by the same number

4. Dividing both sides by the same number

3 0

3 years ago

Match the following items by evaluating the expression for

stich3 [128]

Answer:

x^-2 = 1/4

x^-1 = -1/2

x^0 = 1

x^1 = -2

x^2 = 4

Step-by-step explanation:

got it right

5 0

3 years ago

A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hit the ground. a.Find

Lyrx [107]

A.)
s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]

b.)
s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \]

4 0

3 years ago

Solve for x, I'm confused

IrinaVladis [17]

Both angles have to be 90 so if you find the value for x for one you get the other one ahmatically answer is 22 btw :)

8 0

2 years ago

Read 2 more answers

Find the coordinates of the point where the line <img src="https://tex.z-dn.net/?f=y%3D5x%2B7%5C%5C" id="TexFormula1" title="y=5

Anvisha [2.4K]

Answer:

(0, 7)

Step-by-step explanation:

The point that crosses the y-axis is called the y-intercept of the line.

We are given an equation of the line and we need to determine the y-intercept. This can be done by determining the constant in the equation.

What are constants?

Constants are such terms that include only numbers. There should be no variables in constants.

We know that:

$\bullet \ \text{Given equation of line: y = 5x + 7}$

The constant we can see in the equation is "7". Therefore, the y-intercept is 7.

Note: The y-intercept of the line must have an x-coordinate of 0.

Therefore,

⇒ Coordinates of y-intercept: (x, y) ==> (0, 7).

7 0

2 years ago