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solniwko [45]
2 years ago
11

A trapezoid has an area of 20 cm2 and a height z cm. The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm. Find the

height, z, of the trapezoid. In your final answer, include all of the formulas and calculations necessary.
Mathematics
1 answer:
Brums [2.3K]2 years ago
6 0

Answer: 2.11cm

Step-by-step explanation:

Given the following :

The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm

The area of trapezoid is calculated using the formula:

1/2(a + b) × h

Where ;

a = Length of side 1

b = length of side 2

h = height

Take a = (2z + 3) and b = (6z – 1), h = z

Therefore ;

1/2 (2z + 3 + 6z - 1) × z

Opening the bracket

(z + 1.5 + 3z - 0.5) × z

(4z + 1 ) × z = 20cm^2

4z^2 + z = 20cm^2

Using Quadratic formula:

4z^2 + z - 20 = 0

a = 4, b = 1, c = - 20

(-b±√b^2 -4ac) / 2a

Z = 2.11 or - 2.364

z cannot be negative, therefore,

Z = 2.11 cm

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Answer:

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Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

\text{Area of circle}=\pi r^2, where r represents radius of the circle.

\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2

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\text{Exact area of the sidewalk}=40 \pi\text{ m}^2

Therefore, the exact area of the side walk is 40 \pi\text{ m}^2

To find the approximate area of side walk let us substitute pi equals 3.14.

\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2

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Expand the given power by using Pascal’s triangle. (9a - 10b)^6
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Answer:

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Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

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This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

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Let's replace x with (9a) and y with (-10b) in the expansion:

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((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

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