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3 years ago

1. By what factor did the medicine decrease in the first hour and a half? Explain how you know.

Mathematics

1 answer:

bekas [8.4K]3 years ago

3 0

Answer:

4/9

Step-by-step explanation:

At t = 0 ; volume = 270

At t = 1.5 ; volume = 80

y = P(1 - r)^t

y =ab^x (exponential)

a = initial amout at t = 0

y = final amount

t = 1.5

80 = 270b^t

80/270 = b^t

8/27 = b^1.5

8/27 = b^3/2

b^3/2*2/3 = (8/27)^2/3

Cube root of 8/27 = 2/3

Square of 2/3 = (2/3)^2 = 4/9

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malfutka [58]

Answer:

eight more than a fifth of a number

Step-by-step explanation:

k/5 is one-fifth of a number. When 8 is added to it, the result is ...

eight more than a fifth of a number

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There is no multiplication by 5, so any phrasing with "five times" is incorrect.

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3 years ago

The circumference of a circle is 60pi cm. What is the radius of the circle ?

Margaret [11]

Answer:

30 cm

Step-by-step explanation:

The circumference of a circle is

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4 years ago

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3 years ago

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Kuzi and Joanne live 130 km apart. They start travelling towards each other at the same time. If Kuzi covers 16 km every 2 hours

Zepler [3.9K]

Using the speed - distance relationship, the distance traveled by Joanne would be 55.714 km

Kuzi's speed :

16/2 = 8km / hr

Joanne's speed :

6km/hr

Let time taken = t

Total distance traveled :

8t + 6t = 130

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t = 130/14

t = 9.2857142 hours

Therefore, distance traveled by Joanne :

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Therefore, distance traveled by Joanne will be 55.714 km

Learn more : brainly.com/question/18796573

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3 years ago

How do you determine where f(x)=cos^(-1)(lnx) is continuous?

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$\ln x$ is continuous over its domain, all real $x>0$ .

Meanwhile, $\cos^{-1}y$ is defined for real $-1\le y\le1$ .

If $y=\ln x$ , then we have $-1\le \ln x\le1\implies \dfrac1e\le x\le e$ as the domain of $\cos^{-1}(\ln x)$ .

We know that if $f$ and $g$ are continuous functions, then so is the composite function $f\circ g$ .

Both $\cos^{-1}y$ and $\ln x$ are continuous on their domains (excluding the endpoints in the case of $\cos^{-1}y$ ), which means $\cos^{-1}(\ln x)$ is continuous over $\dfrac1e$ .

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3 years ago