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Vanyuwa [196]
3 years ago
9

Find the area of the shape shown below. 9 3 As units

Mathematics
1 answer:
Vikki [24]3 years ago
7 0
If the base for the top is 9, the base for the bottom, 3, and the height is 3, your answer should be 18. Hope this helps
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Explain which variables would be included when using technology to calculate the present value of a lump sum and to calculate th
koban [17]

Answer:

a. Present value of a lump sum =

PV = FV / ( 1 + i )ⁿ

b. Present value of an annuity =

P = PMT x ((1 – (1 / (1 + r)⁻ⁿ )) / r)

Step-by-step explanation:

a. Present Value of a Lump sum =

PV = FV / ( 1 + i )ⁿ

Where variables in the formula are explained as follows

PV = Present Value of the given amount today

FV = Future Value of the given amount

i = Discount rate

n = Number of periods

b. Present value of an annuity is given as:

P = PMT x ((1 – (1 / (1 + r)⁻ⁿ)) / r)

The variables in the equation are explained as the follows:

P = the present value of annuity

PMT = Payment per period or the amount in each annuity payment

r =  the interest or discount rate

n = total number of periods or the number of payments left to receive

8 0
3 years ago
As a membership fee a health club charges a one time amount of $40 and charges $25 for each month. The total fee after m months
ICE Princess25 [194]
First you need to set up an equation y = mx + b. m would be the monthly charge and b would be the one time fee. x represents the number of months.
To solve for the number of months with a total price of 240 we substitute 240 in for y and solve for x.
240 = 25x + 40
subtract 40 from each side
200= 25x
divide by 25
8 = x
8 months

10 + 7r = 45
7r = 35
r = 5
5 miles
3 0
3 years ago
Which holds the more capacity 0.75 litres or 350ml
RSB [31]

Answer:

0.75 liters

Step-by-step explanation:

1000ml in 1 liter so 0.75*1000=750ml

750ml > 350ml

6 0
2 years ago
Please dont put any files or links. answer each equation please.
Lynna [10]

Answer:

23 thousandths. <em><u>=</u></em><em><u> </u></em> 23 ÷ 10^3

9+4 × (6÷3) <em><u>></u></em> (9+4×6) ÷ 3

5 tens + 2 hundredths. <em><u><</u></em> 50.20

810.6 ÷ 10. <em><u>=</u></em> 8.106 × 10

7 0
3 years ago
We want to find the zeros of this polynomial:
fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>

p(x) = x^2(2x+3) <u>-9(2x+3)</u>

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0
3 years ago
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