Answer:
x^2 y ^4 ∛ [x^2 y ^2 ] is the answer that I got
Step-by-step explanation:
Answer:
m=3/4
Step-by-step explanation:
first, let's put the line 4x+3y=9 from standard form (ax+by=c) into slope-intercept form (y=mx+b)
we have the equation 4x+3y=9
subtract 4x from both sides
3y=-4x+9
divide by 3
y=-4/3x+3
perpendicular lines have slopes that are negative and reciprocal. If the slopes are multiplied together, the result is -1
so to find the slope of the line perpendicular to the line y=-4/3x+3, we can take the slope of y=-4/3x+3 (-4/3) multiply it by a variable (this is our unknown value), and have that set to -1
(m is the slope value)
-4/3m=-1
multiply by -3/4
m=3/4
therefore the slope of the perpendicular line is 3/4
hope this helps!! :)
Answer:
9) slope of AC = slope of FH
Equation of the line is y = - x + 5
10) Area = 320
Step-by-step explanation:
For 9, the only thing similar IS the slope of the hypotenuse because the triangles are along the same line. Unless they're asking for the equation of the line, then that's just using the point slope equation which is:
y = - x + 5
For 10, just multiply 4 and 5 by 4 to get 16 and 20. Then multiply 16 and 20 to get 320.
There are 6 different ways:
23,598
23,958
25,398
25,938
29,538
29,358
