<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
Answer:
Just read the step by step
Step-by-step explanation:
Ok so what you want to do this split the numbers up into sections for example 15-20 find numbers through those numbers. Then count how many there are. After putting them in the blank space and the use the graph to put the same number in. Hope this helps!
Answer:
( -1, 15/2) or ( -1, 7 1/2)
Step-by-step explanation:
Formula: ( (x1 + x2)/2, (y1 + y2)/2 )
1. ( (-4 +6)/2, (8 + 7)/2 ) Plug in
2. ( -2/2, 15/2) Add/Subtract
3. ( -1, 15/2) or ( -1, 7 1/2) Divide
When you have lines in graphs for ex
Y=2x+7
2x is the rate of change
7 is the instant amt if the x=0 (or the y-intercept)
The answer is B you jump -5
