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3 years ago

3/5+1/2=?+?=?,or? ; please DONT explain the anwser and how to do it i would just like the anwser this is what this site is for

1 answer:

8 0

Hint: Make both the denominators of both fractions equal 10, then multiply both numerators by the number you would need to make the denominator 10.

So, If you make 3/5 into 3/10, then you would need to multiply the 3 by 2, since 5x2=10. You do the same thing to the other fraction, 1/2 to 1/10, then you multiply the 1 by 5, since 2x5=10.

Then you just add 6/10 and 5/10 and there is your answer.

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I need to know what is the m< DBC?

Artist 52 [7]

Answer:

120

Step-by-step explanation:

The sum of the angles is 180 since it forms a straight line

2x+ x+90 = 180

Combine like terms

3x +90=180

Subtract 90 from each side

3x+90-90=180-90

3x= 90

Divide each side by 3

3x/3 = 90/3

x = 30

We want angle DBC = x+90

= 30+90

=120

5 0

3 years ago

Read 2 more answers

A student believes that a certain 6-sided number cube, with the numbers 1 to 6, is unfair and is more likely to land with a 6 fa

igomit [66]

Answer:

third one

Step-by-step explanation:

7 0

3 years ago

Can any one here please help me in this math problem I really need help

MArishka [77]

Answer:

The volume of the solid is the volume of the prism minus the volume of the cylinder.

For the cylinder, diameter = d = 4 cm

radius = d/2 = (4 cm)/2 = 2 cm

V = volume of prism - volume of cylinder

The volume of a prism is length times width times height.

The volume of a cylinder is pi times the square of the radius times the height.

V = LWH - (pi)r^2h

V = 6 cm * 6 cm * 15 cm - (pi)(2 cm)^2(15 cm)

V = 540 cm^3 - 60pi cm^3

V = (540 - 60pi) cm^3

5 0

3 years ago

Factor x2 – 8x + 15.<br><br> Which pair of numbers has a product of ac and a sum of b?

vichka [17]

Answer:

(x - 5)(x - 3)

Step-by-step explanation:

${x}^{2} - 8x + 15 \\ = {x}^{2} - 5x - 3x + 15 \\ = x(x - 5) - 3(x - 5) \\ = (x - 5)(x - 3) \\ \\ ac = ( - 5) (- 3) = 15 \\ a + c = - 5 - 3 = - 8$

8 0

4 years ago

Two positive integers have a sum of 10 and a product of 21. What are the integers?

lara [203]

Answer:

Step-by-step explanation:

$x,y-\text{positive integers}\\\\\text{The system of equations:}\\\\\left\{\begin{array}{ccc}x+y=10&\text{subtract}\ y\ \text{from both sides}\\xy=21\end{array}\right\\\\\left\{\begin{array}{ccc}x=10-y&(1)\\xy=21&(2)\end{array}\right\\\\\text{substitute (1) to (2):}\\\\(10-y)(y)=21\qquad\text{use the distributive property}\ a(b-c)=ab-ac\\\\10y-y^2=21\qquad\text{subtract 21 from both sides}\\\\-y^2+10y-21=0\qquad\text{change the signs}\\\\y^2-10y+21=0\\\\y^2-3y-7y+21=0\\\\y(y-3)-7(y-3)=0$

$(y-3)(y-7)=0\iff y-3=0\ \vee\ y-7=0\\\\y-3=0\qquad\text{add 3 to both sides}\\\\y=3\\\\y-7=0\qquad\text{add 7 to both sides}\\\\y=7\\\\\text{Put the value of}\ y\ \text{to (1):}\\\\x=10-3=7\ or\ x=10-7=3$

7 0

3 years ago