Answer: A(4,-1)-> A'(-4,-1) . B(3,-3)->B'(-3, -3) . C(0,2) -> C' (0,2)
Step-by-step explanation:
Pls note that any point P with coordinates Xp and Yp refecting over y-axis will have the image P' with coordinates -Xp and Yp.
So the image of A(4,-1)-> A'(-4,-1)
image of B(3,-3)->B'(-3, -3)
image of C(0,2) -> C' (0,2) C reflects to itself