Question

The graph of f(x) = 24x^2 + 63x +34/ 4x + 3 has an oblique asymptote at y =

Answer 1

Correct answer is C). 6X+11

Step-by-step explanation:

The given function f(x)= $\frac{24x^{2} +63x + 34 }{4x+3}$

On simplying the function f(x),

f(x)= $\frac{6x(4x+3) -18x +63x + 34 }{4x+3}$

f(x)= $\frac{6x(4x+3) +45x + 34}{4x+3}$

f(x)= $\frac{6x(4x+3) +11(4x+3)+x-33 + 34 }{4x+3}$

f(x)= $\frac{6x(4x+3) +11(4x+3)+x+1}{4x+3}$

f(x)=$(6x+11)+\frac{(x+1)}{4x+3}$

From above equation

"(6x+11)" is Oblique asymptote and $\frac{(x+1)}{4x+3}$ is vertical asymptote

Therefore, Correct answer is C). 6X+11

Answer 2

Answer:C

Step-by-step explanation: