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ch4aika [34]
2 years ago
12

24 + (-9) - 44 + 33 - 17 word problem form

Mathematics
1 answer:
pashok25 [27]2 years ago
7 0
Twenty four plus (negative nine) minus forty-four plus thirty three minus seventeen.
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A number line going from 1 to 13. 1 dot is above 1. 3 dots are above 2. 1 dot is above 3. 3 dots are above 4. 1 dot is above 5.
aliina [53]

Answer:

Answer: C) The mean will increase more than the median, but both will increase.

Step-by-step explanation:

I got it right on the test review.

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Solve this inequality ​
8090 [49]
X is greater than or equal to -5
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Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a
EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, \sin x and \cos x are defined for all real numbers.

\tan x=\frac{\sin x}{\cos (x)}, this function is not defined where \cos x=0.

\cot x=\frac{\cos x}{\sin (x)}, this function is not defined where \sin x=0.

\csc x=\frac{1}{\sin (x)}, this function is not defined where \sin x=0.

For option A

The domain of f(x)=\sin(x) is all real numbers.

The domain of g(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

For option B

The domain of f(x)=\cos(x) is all real numbers.

The domain of f(x) =csc(x) is x\ne n\pi

For option C,

The domain of G(x) =tanx is x\ne \frac{(2n+1)\pi}{2}

The domain of f(x) =cot(x) is x\ne n\pi

For option D;

The domain of f(x) =cot(x) is x\ne n\pi

The domain of f(x) =csc(x) is x\ne n\pi

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Step by step explanation:

7 0
3 years ago
Is the enlargement or a reduction? Find the scale factor of the dilation.<br> Explain
malfutka [58]

Good evening ,

Answer:

In this case the dilation is a reduction (as you can see the image triangle is smaller than the original triangle)

and also the scale factor = OA’/OA = 2/6 = 1/3

since  -1 < 1/3 < 1 then it’s a reduction.

Step-by-step explanation:

Look at the photo below for more details (notice OA’ and OA).

________________________________________________

:)

4 0
2 years ago
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