You can use the midpoint formulae as I have in the picture below
To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer:
D 49.1
Step-by-step explanation:
Hope it helps
have a great day
This is already written in scientific notation, but if you are asking what the answer would be written out it is: 400000
Answer:
-2
Step-by-step explanation:
