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What you want to do is change the variable positions of X and Y
So it would be a new equation of
x = 1/2y + 3
Then you would need Y to be by itself so you solve for that
x-3 = 1/2 y
then,
2(x-3) = y
Your inverse function is 2(x-3) = y
Hope this helped :D
Answer:
c · 1 = c
Step-by-step explanation:
Answer:
300
Step-by-step explanation:
Just because it makes sense.
Answer:
x=-5 and x=-1.5
Step-by-step explanation:
The given function is

The points of discontinuity occurs at where the denominator is zero.

We solve by factoring.
We first split the middle term:

We factor by grouping:


The points of discontinuity occur at x=-5, and x=-1.5