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Molodets [167]
3 years ago
11

How far is Raleigh from Poplar Bluff?

Mathematics
2 answers:
suter [353]3 years ago
7 0

Answer:

12 hr 1 min (777.7 mi) this is the correct answer

nata0808 [166]3 years ago
5 0

Answer:

12 hr 1 min

hope this helps

have a good day :)

Step-by-step explanation:

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What is 4/4 as a decimal
Marina86 [1]

Answer:

4/4 as a decimal is 1.00 because 4/4 is one whole

Step-by-step explanation:

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4 glue sticks cost $7.76<br><br> Which equation would help determine the cost of 13 glue sticks?
Elza [17]

Answer:

y=1.94x

13 glue sticks cost $25.22.

Step-by-step explanation:

4 blue sticks cost $7.76, this means that one glue stick costs

$7.76/4 = $1.94.

Let y be the cost of the glue sticks, and x be the number of glue sticks; then

\boxed{y=1.94x}

We can use this equation to find the cost of 13 glue sticks; we just put x=13\ into our equation and it gives:

y=1.94(13)=25.22

So 13 glue sticks cost $25.22.

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Classify the following number -7
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Its classified as an Integer

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I need help with math, giving 15 points! (And brainiest)
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C

Step-by-step explanation:

3x + y + x - 6 + y

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Alex took 31 exams for 5 years studying at the MaPhAs University. Each year, he took more exams than the previous year. During h
katen-ka-za [31]

Answer:

The fourth year he took 8 exams

Step-by-step explanation:

We must do it by trial and error:

We must start from the first year:

A = 1 exam

If the first year he took 1 exam, the last year he did 3, but this answer is not possible because the rule that the more the years pass, the more exams he does, is not fulfilled.

A = 2 exams

In this case, if it is true that each year increases, but it does not meet the total rule, since:

Year 1 = 2

Year 2 = 3

Year 3 = 4

Year 4 = 5

Year 5 = 6

2 + 3 + 4 + 5 + 6 = 20

A = 3 exams

Therefore the fifth year would be 9, therefore it would be:

Year 1 = 3

Year 2 = 4

Year 3 = 5

Year 4 = 6

Year 5 = 9

3 + 4 + 5 + 6 + 9 = 27

This means that we are missing 4 units to reach 31, therefore we must add 4 units between years 2, 3 and 4, but always bearing in mind that each year should increase with respect to the previous one.

If we add 2 exams to year 4, 1 exams to year 3 and 1 exam to year 2, we would have the following results:

Year 1 = 3

Year 2 = 5

Year 3 = 6

Year 4 = 8

Year 5 = 9

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Which means that in the fourth year he took 8 exams

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