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kobusy [5.1K]
3 years ago
15

Find the inverse of the matrices if they Exist. Use the algorithm introduced in the section. [1 0 -2 -3 1 4 2 -3 4]

Mathematics
1 answer:
KiRa [710]3 years ago
6 0

Answer:

\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]

Step-by-step explanation:

Given is a matrix 3x3 as

\left[\begin{array}{ccc}1&0&2\\-3&1&4\\2&-3&4\end{array}\right]

|A| =2 hence inverse exists.

Cofactors are 16   20   7

                        6     8    3

                         2     2    1

Hence inverse =

\frac{1}{2} \left[\begin{array}{ccc}16&6&2\\20&8&2\\7&3&1\end{array}\right]

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6 0
1 year ago
If (x + 2 ) is a factor of x3 − 6x2 + kx + 10, k =
BartSMP [9]
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8 0
3 years ago
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Juan says that 8, 1 3/4, and -12 are all integers. Is he correct? Explain your answer. Please help me fast
monitta
No, he is not right.

Integer is a number that can be written without a fractional component, and 1 3/4 doesn't.

Here's an image for you to better understand. 


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3 years ago
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Im bad at explaining but I hope you now kindof get it

3 0
3 years ago
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