Answer:
top right
Step-by-step explanation:
it is the trapizoid
To solve this, we need to know how to find the mean of a set of data and how to find the median of a set of data.
To find the mean, or often called the average, we should add all of the values up, and then divide it by the number of values.
588+838+691+818+846+725+605+732+750 = 6593
6593/9=732.556
The problem tells us we should round to the nearest point, so our mean credit score is 733.
To find the median, we need to order the data from lowest to highest and find out which credit score(s) are right in the middle. If there are 2 in the middle, we simply should add them and divide by 2 to get our median. An easy way to do this is after you order them, you simply cross off one on each side until there is only 1 (or 2) left.
588 605 691 725 732 750 818 838 846
605 691 725 732 750 818 838
691 725 732 750 818
725 732 750
732
Since we only have one number in the middle, we are done with the median! We know our median is 732.
Now we simply need to compare them and subtract the lower one from the higher one.
Mean:733
Median: 732
733>732
We know the mean is bigger, so we should subtract the median from the mean.
733=732=1
Using the logic above, we can see that the mean is 1 point higher than the median.
Answer:
A The data is proportional and the unit rate per package is $8 This is because y= 8x
Step-by-step explanation:
/y relationship is no of packages = 1 x/ = total cost to ship = 8 = 8/1 = 16/2 = 24/3 = 32/4 means they are all proportional to 8/1 = 8 y = 8x see graph attached
<span>C(15,9) * (1/2)^9 * (1/2)^6 = 5005/32768 = .153 approx</span>
Given equation of the Circle is ,
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
Here we can say that ,
• <u>Radius</u> = 5 units
• <u>Centre </u> = (0,0)
<u>Finding</u><u> </u><u>distance</u><u> between</u><u> </u><u>the </u><u>two </u><u>points</u><u> </u><u>:</u><u>-</u><u> </u>
- Here we can see that the distance of point from centre is less than the radius.
<u>Hence </u><u>the</u><u> </u><u>point</u><u> </u><u>lies </u><u>within</u><u> </u><u>the </u><u>circle</u><u> </u><u>.</u>