I hope the choices for the numerators of the solutions are given.
I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.
The standard form of a quadratic equation is :
ax² + bx + c = 0
And the quadratic formula is:
x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}
So, first step is to compare the given equation with the above equation to get the value of a, b and c.
So, a = 10, b = -19 and c = 6.
Next step is to plug in these values in the above formula. Therefore,




So, 

So, 
Hope this helps you!
Answer:
y = 0.1x - 4
Step-by-step explanation:
Given the following data;
Points on the x-axis (x1, x2) = (-3, 7)
Points on the y-axis (y1, y2) = (-7, -6)
First of all, we would find the slope;
Mathematically, slope is given by the formula;
Substituting into the equation, we have;
Slope = (-6 - (-7))/(7 - (-3))
Slope = (-6 + 7)/(7 + 3)
Slope = 1/10
Slope = 0.1
Next, we would write the equation using the formula;
y - y1 = m(x - x1)
y - (-7) = 0.1(x - (-3))
y + 7 = 0.1(x + 3)
y + 7 = 0.1x + 3
y = 0.1x + 3 - 7
y = 0.1x - 4
I'm sorry this is gauge is there anymore info
The answer is 5. Hope this helps