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lisov135 [29]
3 years ago
13

I NEED HELP ASAP PLEASE

Mathematics
1 answer:
aniked [119]3 years ago
3 0
Graph question: (0,0) & (3,6)
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Solve 0= 2t^3-21t^2+ 40t
sukhopar [10]
0=2t^3-21^2+40t
switch sides
2t^3-21t^2+40t=0
solve factoring 
t(t-8)(2t-5)=0
using the zero factor principle
t=0

solve
t-8=0:t=8
solve
2t-5=0:t= \frac{5}{2}
t=0,t=8,t= \frac{5}{2}
Hope this helps

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