The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Answer:
p = 1.2
Step-by-step explanation:
Bring 3.9 to the other side of the equation.
-10.9p = -13.08
p = 1.2
Answer:
If my cousin gave me $16 ( my real cousins never did T_T) and I am left with $8 while buying a present. The present cost $8...
Wow, I thought I was bad at math
Answer:
The triangle is isosceles and not right
Hope this helps.
When distributed it comes out to be 12m^7 n^6
