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3 years ago

Let a(x) be the amount of money remaining on Hillary's gift card after purchasing x apps on her phone.

Mathematics

2 answers:

Contact [7]3 years ago

6 0

Answer:

35, 35, & 12.

Step-by-step explanation:

i did the test and i got it right :D

Annette [7]3 years ago

3 0

Answer:

she purchased 12 apps costs 12 *1.25 = 15 . So , she spent 15 ... Since a(12) = 35, Hillary will have 35 dollars remaining on her card after purchasing 12 apps.

Step-by-step explanation:

hopefully this helps

You might be interested in

The half-life of a radioactive kind of rhythium is 1 year. If you start with 64 grams of it, how much will be left after 3 years

finlep [7]

Answer:

Step-by-step explanation:

64×0.5³ = 8 grams

5 0

3 years ago

The amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.5 hours and a stan

Ber [7]

Answer:

When sample size increases from n = 23 to n = 35, the mean of the distribution of sample means remains same but the standard deviation of the distribution of sample means decreases from 0.073 to 0.059.

Step-by-step explanation:

We are given the amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.5 hours and a standard deviation of 0.35 hour.

Random samples of size 23 and 35 are drawn from the population and the mean of each sample is determined.

Here, $\mu$ = population mean = 7.5 hours

$\sigma$ = population standard deviation = 0.35 hour

Let $\bar X$ = sample mean

(a) The random samples of size of n = 23 is drawn from the population;

So, mean of the distribution of sample means = $\mu$ = 7.5 hours

Standard deviation for the distribution of sample means is given by;

s = $\frac{\sigma}{\sqrt{n} }$ = $\frac{0.35}{23}$ = 0.073

(b) The random samples of size of n = 35 is drawn from the population;

So, mean of the distribution of sample means = $\mu$ = 7.5 hours

Standard deviation for the distribution of sample means is given by;

s = $\frac{\sigma}{\sqrt{n} }$ = $} \frac{0.35}{\sqrt{35} }$ = 0.059

(c) So, as we can see that when sample size increases from n = 23 to n = 35, the mean of the distribution of sample means remains same but the standard deviation of the distribution of sample means decreases from 0.073 to 0.059.

4 0

4 years ago

Rationalize the denominator.

Maslowich

If you're using the app, try seeing this answer through your browser: brainly.com/question/3166412

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$\mathsf{\dfrac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}-2\sqrt{y}}}$

Multiply and divide by the conjugate of the denominator, which is $\mathsf{\sqrt{a}+2\sqrt{y}:}$

$\mathsf{=\dfrac{\big(\sqrt{a}+2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}{\big(\sqrt{a}-2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}}\\\\\\ \mathsf{=\dfrac{\big(\sqrt{a}+2\sqrt{y}\big)^2}{\big(\sqrt{a}-2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}}$

The numerator is a square of a sum, and the denominator is the product of a difference and a sum (product of two conjugates). Then, expand the common products:

$\mathsf{=\dfrac{\big(\sqrt{a}\big)^2+2\cdot \sqrt{a}\cdot 2\sqrt{y}+\big(2\sqrt{y}\big)^2}{\big(\sqrt{a}\big)^2-\big(2\sqrt{y}\big)^2}}\\\\\\ \mathsf{=\dfrac{a+4\cdot \sqrt{a}\cdot \sqrt{y}+2^2\cdot \big(\sqrt{y}\big)^2}{a-2^2\cdot \big(\sqrt{y}\big)^2}}$

$\mathsf{=\dfrac{a+4\sqrt{ay}+4y}{a-4y}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

8 0

3 years ago

What is the equation of the following line? Be sure to scroll down first to see

Hoochie [10]

Answer:

y=9x

Step-by-step explanation:

(0,0),(1,9)

when x=0, y=0, means b=0

m is the slope =9

y=9x

3 0

3 years ago

James is a welder who earns $12.50 per hour. He works 8 hours per day, Monday through Friday. How much does James earn in one we

fiasKO [112]

Answer:

12.50 * 8=100 100*5=500. He would earn 500 a week

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers