Answer:
Step-by-step explanation:
eq. of directrix is y-1=0
let (x,y) be any point the parabola.
then\sqrt{ (x-6)^2+(y-2)^2}=\frac{y-1}{(-1)*2}
squaring
x²-12x+36+y²-4y+4=y²-2y+1
x²-12 x+40-1=4y-2y
2y=x²-12x+39=x²-12x+36+3
(x-6)²=2y-3
Graph 1: Domain = 2 <= x < 12
Graph 1: Range = {2,4}
Graph 2: Domain = 3 <= x <= 10
Graph 2: Range = -6 <= y <= 4
Graph 3: Domain = 4 < x < 11
Graph 4: Range = -6 <= y < 2
Answer:
25
Step-by-step explanation:
(6^2+4)−15
(36+4)−15
40−15
25
Answer:
It is either A or B. I am not certain only because I do not know if your assignement is indicating that the underlined greater sign represents an open dot or a closed dot
Answer:
10y^3+6y
Step-by-step explanation:
