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Hitman42 [59]
3 years ago
7

Here are 20 students in Jacob's homeroom. Five students bring their lunch to school. The rest eat lunch in the cafeteria. In sim

plest form, what fraction of students eat lunch in the cafeteria? By the way this is fraction do you know 2/3 like that you now Those types of fractions of students eat lunch in the cafeteria. What is the answer
Mathematics
1 answer:
murzikaleks [220]3 years ago
5 0

Answer: 3/4

Step-by-step explanation:

Number of students in Jacob's homeroom = 20.

Number of students who bring their lunch to school = 5

Since the rest eat lunch in the cafeteria, the number of those who eats in the cafeteria will be:

= 20 - 5

= 15

Fraction that eats in the cafeteria will be: = 15/20 = 3/4

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Help me please !!?????????? Question 4
Ne4ueva [31]

from question d = 16t^2 = 56-4t

=》 16t^2 -56 + 4t =0

=》 4t^2 - 14 + t = 0

=》 (4t-7)(t+2) =0

=》 t = 1.75 seconds

4 0
3 years ago
Don ate 160 grams of carbohydrates, 100 grams of fat, and 70 grams of protein today. What is his total calorie consumption for t
Artemon [7]

Answer:

His total calorie consumption for the day is:

Option C. 1.820 kcal

Step-by-step explanation:

Protein and carbohydrates both contain 4 calories per gram, while fat provides 9 calories per gram, then:

1.) 160 grams of carbohydrates contain:

160 grams * (4 cal/gram)=640 cal

2.) 100 grams of fat contain:

100 grams * (9 cal/gram)=900 cal

3.) 70 grams of protein contain:

70 grams * (4 cal/gram)=280 cal


Then, his total calorie consumption for the day is:

T=640 cal + 900 cal +280 cal

T=1,820 cal

T=1,820 cal (1 kcal / 1,000 cal)

T=1.820 kcal

6 0
3 years ago
Helpppp confused
Sveta_85 [38]

Not an expertise on infinite sums but the most straightforward explanation is that infinity isn't a number.

Let's see if there are anything we missed:

 ∞

 Σ  2^n=1+2+4+8+16+...

n=0

We multiply (2-1) on both sides:

       ∞

(2-1)  Σ  2^n=(2-1)1+2+4+8+16+...

      n=0

And we expand;

 ∞

 Σ  2^n=(2+4+8+16+32+...)-(1+2+4+8+16+...)

n=0

But now, imagine that the expression 1+2+4+8+16+... have the last term of 2^n, where n is infinity, then the expression of 2+4+8+16+32+... must have the last term of 2(2^n), then if we cancel out the term, we are still missing one more term to write:

 ∞

 Σ  2^n=-1+2(2^n)

n=0

If n is infinity, then 2^n must also be infinity. So technically, this goes back to infinity.

Although we set a finite term for both expressions, the further we list the terms, they will sooner or later approach infinity.

Yep, this shows how weird the infinity sign is.

5 0
2 years ago
All right triangles are :
uranmaximum [27]
I think that it’s A, Perpendicular (correct me if I’m wrong)
4 0
3 years ago
Read 2 more answers
What is the sum of the solutions to (x − 6)(x + 0.7) = 0 ?
Nonamiya [84]

Answer:

5.3

Step-by-step explanation:

(x − 6)(x + 0.7) = 0

using the zero product property

x-6=0   x+.7 =0

x-6+6 = 0+6       x+.7 -.7 = 0-.7

x = 6                   x= -.7

sum of the solutions

6+-.7 = 5.3

5 0
3 years ago
Read 2 more answers
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