Just find the slope
that is ((f(6)-f(2))/(6-2)
f(6)=6^2+5(6)-8=36+30-8=58
f(2)=2^2+5(2)-8=4+10-8=6
average is (f(6)-f(2))/(6-2)=(58-6)/(4)=52/4=13
average rate of change is 13
A) The answers are:
the first frequency - 428.75 Hz
the second frequency - 1286.25 Hz
the third frequency - 2143.75 Hz
The frequency (when the pipe is closed) is: f = v(2n - 1)/4L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe
We know:
v = 343 m/s
L = 20 cm = 0.2 m
1. The first frequency (n = 1):
f = 343 * (2 * 1 - 1) / 4 * 0.2 = 343 * 1 / 0.8 = 428.75 Hz
2. The second frequency (n = 2):
f = 343 * (2 * 2 - 1) / 4 * 0.2 = 343 * 3 / 0.8 = 1286.25 Hz
3. The third frequency (n = 3):
f = 343 * (2 * 3 - 1) / 4 * 0.2 = 343 * 5 / 0.8 = 2143.75 Hz
B) The answers are:
the first frequency - 857.5 Hz
the second frequency - 1715 Hz
the third frequency - 2572.5 Hz
The frequency (when the pipe is open) is: f = vn/2L
v - the speed of sound
n - the frequency order
L - the length of the organ pipe
We know:
v = 343 m/s
L = 20 cm = 0.2 m
1. The first frequency (n = 1):
f = 343 * 1 / 2 * 0.2 = 343 / 0.4 = 857.5 Hz
2. The second frequency (n = 2):
f = 343 * 2 / 2 * 0.2 = 686 / 0.4 = 1715 Hz
3. The third frequency (n = 3):
f = 343 * 3 / 2 * 0.2 = 1029 / 0.4 = 2572.5 Hz
Answer:
1 row with 16 jars, 2 rows with 8 jars and 4 rows with 4 jars are the arrays in order to arrange jars.
Step-by-step explanation:
Since, there are 16 jars of spices and he has to arrange them in arrays, then he can arrange 16 jars each in one row, 8 jars each in 2 rows and 4 jars each in 4 rows.
These are the only possibilities without breaking the jars into pieces.
Area of circle = pi r^2 = 78.54
r^2 = 78.54 / pi = 25
r = 5 inches
Each line from centre of the circle to a point on the hexagon = 5 ins
so consider one of the 6 congruent triangles formed from these lines:-
Vertex angle = 60 degrees
sin 30 = 0.5s / 5 (where s = one side of the hexagon).
0.5s = 5*0.5 = 2.5
s = 2.5 / 0.5 = 5
So the perimeter of the hexagon is 6*5 = 30 inches
The line a and line b are parallel to each other since if you draw another line or a third plane and it contains both points both in line a and in line b it means that this third plane passes through to the both lines a and b. In order to achieve both lines a and b can be passed by the third plane, they should be parallel to each other.
