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rjkz [21]
2 years ago
8

Help please!! im stuck

Mathematics
1 answer:
Lady_Fox [76]2 years ago
7 0

Answer:

<u>No</u>

Step-by-step explanation:

3/5 or 3 ÷ 5 = 0.60

6/7 or 6 ÷ 7 = about 0.8571

these two numbers/decimals are obviously not the same, making them inequivalent

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Two dices are tossed. What is probability that you will see even numbers on both dices? Answer should be in reduced
zimovet [89]

Answer:

3/6

Step-by-step explanation:

Well 3 is half of 6 and if you were to turn that into a fraction it would either be 3/6 or 1/2.

8 0
3 years ago
The base of a parallelogram is 3.2 centimeters and the height is 1.8 centimeters. What is the area of the parallelogram? Do not
jeka94

Answer:

A = 5.76 cm²

Step-by-step explanation:

3.2 cm x 1.8 cm = 5.76 cm²

3 0
2 years ago
Read 2 more answers
What are the solution(s) of x squared minus 4 = 0? x = negative 4 or x = 4 x = negative 2 or x = 2 x = 2 x = 4
frosja888 [35]

Answer:

Step-by-step explanation:

The expression is

x^2 - 4

This is a quadratic expression.

To find the solution, we will equate the the expression to zero. It becomes

x^2 - 4 = 0

Add 4 to the left hand side of the equation and the right hand side of the equation. It becomes.

x^2 - 4 + 4 = 0 + 4

x^2 = 4

Take square root of the right hand side of the equation and left hand side of the equation. It becomes

√x^2 = √4

x = ± 2

x = 2 or x = - 2

7 0
3 years ago
Read 2 more answers
Find the vector projection of B onto A if A = 5i + 11j – 2k,B = 4i + 7k​
valkas [14]

Answer:

\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\

Step-by-step explanation:

Given A = 5i + 11j – 2k and B = 4i + 7k​, the vector projection of B unto a is expressed as proj_ab = \dfrac{b.a}{||a||^2} * a

b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)

note that i.i = j.j = k.k  =1

b.a = 5(4)+11(0)-2(7)

b.a = 20-14

b.a = 6

||a|| = √5²+11²+(-2)²

||a|| = √25+121+4

||a|| = √130

square both sides

||a||² = (√130)

||a||²  = 130

proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\

<em>Hence the projection of b unto a is expressed as </em>\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\<em></em>

7 0
3 years ago
PLEASE HELP DUE TOMMOROW!!!!!
Marta_Voda [28]
Let X= # of days, y= finial cost. Part A= 12+7x=y. Part B= 12+7(18)= $138. Part c= 12+7(187)= $1,321
8 0
3 years ago
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