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zzz [600]
3 years ago
10

1 Subtract and simplify.

Mathematics
1 answer:
tresset_1 [31]3 years ago
7 0
1. y^2 - 3y - 5 - (-y^2 - 7y + 4) = y^2 - 3y - 5 + y^2 + 7y - 4 =
    2y^2 + 4y - 9 <===

2. 6xy^3z * 3x^2yx^2 = 18x^5y^4z

3. -3x^3(-2x^2 + 4x - 3) = 6x^5 - 12x^4 + 9x^3

4. (6p + 2)^2 = (6p + 2)(6p + 2) = 36p^2 + 12p + 12p + 4 = 
    36p^2 + 24p + 4.....coefficient is 24

5. (x - 5)(x^2 - 2x - 6) = x(x^2 - 2x - 6) - 5(x^2 - 2x - 6) =
     x^3 - 2x^2 - 6x - 5x^2 + 10x + 30 =
     x^3 - 7x^2 + 4x + 30 <===
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NeTakaya

Answer:

D. 22,417 feet

Step-by-step explanation:

Fine the diagram in the attachment for proper elucidation. Using the SOH, CAH, TOA trigonometry identity to solve for the distance (x) from the plane (P) to the observer (O), the longest side x is the hypotenuse and the side facing the angle of elevation is the opposite.

Hypotenuse = x and Opposite = 15,000feet

According to SOH;

sin 42^0 = \frac{Opposite}{Hypotenuse} \\\\Sin42^0 = \frac{15000}{x}\\ \\x = \frac{15000}{sin42^0}\\\\ \\

x = \frac{15000}{ 0.6691} \\\\x = 22,417 feet

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3 years ago
A 16 foot ladder rests against the side of a house and the base of the ladder is 4 feet away. How high above the ground is the t
PtichkaEL [24]

Answer:

  15.5 ft

Step-by-step explanation:

The geometry of the problem can be modeled by a right triangle with hypotenuse 16 ft and one side length of 4 ft. If x represents the height of the ladder on the building, then the Pythagorean theorem tells us ...

  x^2 + (4 ft)^2 = (16 ft)^2

  x^2 = 240 ft^2 . . . . . . subtract 16 ft^2

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The top of the ladder is about 15.5 ft above the ground.

8 0
3 years ago
Pls help I’m failing
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Answer:

a.

the area of each parallelogram

<em>a. 66</em>

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<em>c. 25</em>

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Step-by-step explanation:

a parallelogram is similar to a rectangle when you are finding the ares, you use the base and the height to find the area. If it helps, like the text suggested, just change them to look like a rectangle and then find the area.

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