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Ber [7]
3 years ago
14

What is the factored form of ...

Mathematics
2 answers:
umka21 [38]3 years ago
5 0

Answer:

(A) I think

Step-by-step explanation:

We you divide x12 and y18,12=4 y=6. Then you take +1 and change it to -1. It should bring you to answer A.

I hope I'm right and I hope this helps:)!

nevsk [136]3 years ago
5 0

Answer:

The answer is A:

(x^{4}y^{6} - 1)(x^{8}y^{12} - x^{4}y^{6} + 1)

Step-by-step explanation:

To solve this question, first apply the exponent rule to the entire equation:

x^{12}y^{18} + 1

= (x^{4}y^{6})^{3} + 1^{3}

Next, we can apply the Sum of Cubes formula. To refresh your memory, the formula is as thus:

x^{3} + y^{3} = (x + y)(x^{2} - xy + y^{2})

So, let's apply this to the equation above:

(x^{4}y^{6})^{3} + 1^{3}

= (x^{4}y^{6} + 1)((x^{4}y^{6})^{2} - x^{4}y^{6} + 1^{2})

= (x^{4}y^{6} + 1)((x^{4}y^{6})^{2} - x^{4}y^{6} + 1^{2})

= (x^{4}y^{6} - 1)(x^{8}y^{12} - x^{4}y^{6} + 1)

Therefore, the answer is A.

Hope this helped!

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Answer:

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Step-by-step explanation:

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90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}}

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}

The confidence interval has an lower limit of \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi - 1.645\sqrt{\frac{\pi(1-\pi)}{n}} and an upper limit of \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = \pi + 1.645\sqrt{\frac{\pi(1-\pi)}{n}}, in which \pi is the sample proportion and n is the size of the sample.

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Step-by-step explanation:

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