Both are not equivlant to the top speed of the model plane because caculator op.
The denominator must be equal to all other denominations
Given:
A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.
To find:
The surface area of the pyramid to the nearest whole number.
Solution:
A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.
Area of a square is



So, area of square base is 100 sq. in.
Area of a triangle is



So, area of each triangular surface is 20 sq. in.
Now, the total surface area of the pyramid is
Total area = Area of square base + Area of 4 congruent triangles.




Therefore, the area of the pyramid is 180 sq. in.
Answer:
(a) = 60
(b) = 70
Step-by-step explanation:
(a) Sum of all the angles of a triangle is 180
This is an equilateral Triangle
which means all the sides are equal since all the sides are equal that means all the angles are equal

(b) this is an isosceles triangle with two equal sides that means the two opposite angles are equal

The angle of depression is 29.0521°. So it is a safe landing.
Step-by-step explanation:
Step 1:
The plane is flying at a height of 25,000 feet and 45,000 feet away from the landing strip. Assume it lands with an angle of depression of x°.
So a right-angled triangle can be formed using these measurements. The triangle's opposite side measures 25,000 feet while the adjacent side measures 45,000 feet. The angle of the triangle is x°.
To determine the value of x, we calculate the tan of the given triangle.

Step 2:
The length of the opposite side = 25,000 feet.
The length of the adjacent side = 45,000 feet.

So x = 29.0521°. Since x < 30°, it is a safe landing.