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Alex
3 years ago
11

Which statement best explains why the graphed relation is not a function?

Mathematics
1 answer:
timurjin [86]3 years ago
5 0
C. A function can only have one y value for an x value
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What is -2m^2-2mn+8-10m+10n+mn+4n^2-5n simplify to
Mrac [35]
Find like terms and group them
3n and 5n are same and 4n^2 and 4n^2 are same
but 3mn and 5n are not and 3n and 2n^3 are not

group like terms
(-2m^2)+(-2mn+1mn)+(8)+(-10m)+(10n-5n)+(2n^2)
add like terms
(-2m^2)+(-mn)+(8)+(-10m)+(5n)+(2n^2)
-2m^2+2n^2-10m+5n-mn+8 is simplest form

4 0
3 years ago
5.
Delicious77 [7]

You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:

<em>a(t)</em> = 40 ft/s²

<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>

<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>

<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>

<em />

<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>

<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>

<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²

<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²

6 0
3 years ago
Can someone please help me?
Andru [333]

Answer:

Use the SINE COSINE and the TANGENT rule

Step-by-step explanation:

1.1st use the Pythagoras theorem to find the value of the other side

2.Now be comfortable to use the rule............................

4 0
2 years ago
12 for 3 books ; 28 for 7
Gelneren [198K]
The answer is 4 because if u divide both equations by eachother you get 4
3 0
3 years ago
Eric buys two plants. One plant is 4 inches tall and grows 2 of an inch per week. Another plant is 3 inches tall and grows
Liula [17]
It’s Abe beacuse it grew 7 inch week and 4 tall 2 week.
3 0
3 years ago
Read 2 more answers
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